🛠️ JEE➗ Maths

\(\sum_{k=0}^6{ }^{51-k} C_3\) is equal to

\({ }^{52} C_4-{ }^{46} C_4\)

\({ }^{52} C_4-{ }^{45} C_4\)

\({ }^{51} C_4-{ }^{45} C_4\)

\({ }^{51} C_3-{ }^{46} C_3\)

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