If \({\text{sec}}^{2}\theta =\frac{4}{3}\), then the general value of θ is ( n \(\in\) Z )

\(\ 2\mathrm{n} \pi \pm \frac{\pi}{6} \)

\(n \pi \pm \frac{\pi}{6}\)

\(2 \mathrm{n} \pi \pm \frac{\pi}{3}\)

\(n \pi \pm \frac{\pi}{3}\)