If the points with position vectors \(6 \hat{i}+11 \hat{j}+11 \hat{k}\), \(\frac{9}{2} \hat{i}+\beta \hat{j}-8 \hat{k}, …

If the points with position vectors \(6 \hat{i}+11 \hat{j}+11 \hat{k}\), \(\frac{9}{2} \hat{i}+\beta \hat{j}-8 \hat{k}, \alpha \hat{i}+10 \hat{j}+13 \hat{k}\) are collinear, then \((19 \alpha-6 \beta)^2\) is equal to

[JEE Main 2023, 8 Apr (Shift 1)]