Let \(\vec{a}=3 \hat{i}-\hat{j}+2 \hat{k}, \vec{b}=\vec{a} \times(\hat{i}-2 \hat{k})\) and \(\vec{c}=\vec{b} \times \hat…
Let \(\vec{a}=3 \hat{i}-\hat{j}+2 \hat{k}, \vec{b}=\vec{a} \times(\hat{i}-2 \hat{k})\) and \(\vec{c}=\vec{b} \times \hat{k}\). Then the projection of \(\vec{c}-2 \hat{j}\) on \(\vec{a}\) is:
[JEE Main 2025, 24 Jan (Shift 2)]
\(2 \sqrt{14}\)
\(\text{Given,}\\ \vec{a}=3\overset{^}{i}-\overset{^}{j}+2\overset{^}{k},\\ \vec{b}=\vec{a}\times \left(\overset{^}{i}-2\overset{^}{k}\right)\text{ }\\ \text{and }\vec{c}=\vec{b}\times \overset{^}{k}\\ \text{Now, }\\ \vec{\mathrm{b}}=\vec{\mathrm{a}}\times \left(\overset{^}{\mathrm{i}}-3\overset{^}{\mathrm{k}}\right)\\ =\left|\begin{matrix}\overset{^}{i} & \overset{^}{j} & \overset{^}{k} \\ 3 & -1 & 2 \\ 1 & 0 & -2\end{matrix}\right|=2\overset{^}{i}+8\overset{^}{j}+\overset{^}{k}\\ \vec{\mathrm{c}}=\vec{\mathrm{b}}\times \overset{^}{\mathrm{k}}=8\overset{^}{\mathrm{i}}-2\overset{^}{\mathrm{j}}\\ \vec{\mathrm{c}}-2\overset{^}{\mathrm{j}}=8\overset{^}{\mathrm{i}}-4\overset{^}{\mathrm{j}}\\ \text{ Projection of }\left(\vec{\mathrm{c}}-2\overset{^}{j}\right)\text{ on }\vec{a}\\ \left(\vec{\mathrm{c}}-2\overset{^}{\mathrm{j}}\right)\cdot \overset{^}{\mathrm{a}}=\frac{⟨8,-4,0⟩\cdot ⟨3,-1,2⟩}{\sqrt{14}}\\ =\frac{28}{\sqrt{14}}=2\sqrt{14}\)
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