A capacitor is connected to a 20V battery through a resistance of \(10\Omega\). It is found that the potential difference across the capacitor rises to 2V in \(1\mu s\). The capacitance of the capacitor is ______ \(\mu F\). Given \(\ln \left(\frac{10}{9}\right)=0.105\)

[JEE Main 2021, 1 Sep (Shift 2)]

Question

A capacitor is connected to a 20V battery through a resistance of \(10\Omega\). It is found that the potential difference across the capacitor rises to 2V in \(1\mu s\). The capacitance of the capacitor is ______ \(\mu F\). Given \(\ln \left(\frac{10}{9}\right)=0.105\)

[JEE Main 2021, 1 Sep (Shift 2)]

YESPYQ · Accepted Answer

Options are free to see. Unlock the correct answer and full explanation with PYQ Pass.

A capacitor is connected to a 20V battery through a resistance of \(10\Omega\). It is found that the potential differenc…

Practice more JEE Physics PYQs