JEEPhysics

Current Electricity

51 JEE Physics previous year questions on Current Electricity — options free on every question; 5 include the answer & explanation free, the rest unlock with PYQ Pass.

Q1 FREE PREVIEW
PYQ
Two identical moving coil galvanometer have resistance and full scale deflection at current.One of them is converted into a voltmeter of full scale reading and the other into an Ammeter of full scale current using appropriate resistors. These are then used to measure the voltage and current in the Ohms law experiment with resistor by using an ideal cell. Which of the following statement(s) is/are correct ? [JEE Advanced 2019]
aThe measured value of will be .
bThe resistance of the Voltmeter will be .
cThe resistance of the Ammeter will be ( round off to decimal place)
dIf the ideal cell is replaced by a cell having internal resistance of then the measured value of will be more than .
✓ Correct answer: a) The measured value of will be .
ExplanationWe have two identical galvanometers: Galvanometer Specifications: Resistance ( ) = 10 Ω Full-scale deflection current ( ​) = 2 μA = 2 × 10⁻⁶ A Conversions:1. Voltmeter: One galvanometer is converted to measure up to 100 mV.2. Ammeter: The other is converted to measure up to 1 mA.These are used in an Ohm's law experiment with a resistor Ω and an ideal cell (no internal resistance initially).Later, the cell is replaced with one having an internal resistance of 5 Ω.We need to evaluate the correctness of the given statements (A, B, C, D).Step 1: Convert Galvanometer to Voltmeter Goal: Measure up to mV = 0.1 V. A voltmeter is created by adding a series resistor ( ​) to the galvanometer.The total resistance ( ) should allow full-scale deflection at 0.1 V. Calculation: | | JEE Total Voltmeter Resistance ( RV​): Statement B: Claims .Verdict: Incorrect (actual ).Step 2: Convert Galvanometer to Ammeter Goal: Measure up to mA = 0.001 A. An ammeter is created by adding a shunt resistor ( ​) in parallel.The shunt diverts most of the current, allowing only μA through the galvanometer.Calculation: ​ ​ Total Ammeter Resistance ( ​): Statement C: Claims .Verdict: Correct (rounded to 2 decimal places).Step 3: Measuring with Ideal Cell Circuit Setup: Voltmeter ( ) is placed in parallel with .Ammeter ( ) is placed in series.Effective Resistance of + Voltmeter: Total Circuit Resistance: Current Measurement: The ammeter reads the current through the entire circuit, but the voltmeter reads the voltage across , not just .Measured Resistance ( ​): Statement A: Claims .Verdict: Correct (since falls in this range).Step 4: Effect of Internal Resistance ( ) When the cell has internal resistance: The total resistance increases to | | JEE The current decreases, but the voltmeter still measures the voltage across ​.Measured Resistance: Statement D: Claims Verdict: Incorrect (actual ).Final Answer Correct Statements: A and C.
Q2 FREE PREVIEW
PYQ
Given below are two statements : Statement-I: The equivalent emf of two non- ideal batteries connected in parallel is smaller than either of the two emfs. Statement-II : The equivalent internal resistance of two non-ideal batteries connected in parallel is smaller than the internal resistance of either of the two batteries. In the light of the above statements, choose the correct answer from the options given below.
aBoth Statement-I and Statement-II are true
bBoth Statement-I and Statement-II are false
cStatement-I is true but Statement-II is false
dStatement-I is false but Statement-II is true
✓ Correct answer: d) Statement-I is false but Statement-II is true
ExplanationThe equivalent EMF of two non-ideal batteries connected in parallel is given by: If , where are the EMFs of the two batteries and are their internal resistances.
Q3 FREE PREVIEW
PYQ

A wire of resistance \(9\text{ }\Omega\) is bent into the shape of an equilateral triangle. What is the equivalent resistance between any two vertices of the triangle?

(Shift I Memory Based)

a

\(1\text{ }\Omega\)

b

\(2\text{ }\Omega\)

c

\(3\text{ }\Omega\)

d

\(4\text{ }\Omega\)

✓ Correct answer: b)

\(2\text{ }\Omega\)

Explanation
  • Total resistance of the wire: \({R}_{\text{total}}=9\text{ }\Omega\)
  • Resistance of each side: \({R}_{\text{side}}=\frac{{R}_{\text{total}}}{3}=3\text{ }\Omega\)
  • Between any two vertices, there are two paths:
    1. Direct resistance \({R}_{1}=3\text{ }\Omega\).
    2. The other two sides (\({R}_{2}\)) add up: \({R}_{2}=6\text{ }\Omega\)
  • These are in parallel: \({R}_{\text{eq}}=\frac{{R}_{1}{R}_{2}}{{R}_{1}+{R}_{2}}=\frac{(3)(6)}{3+6}=2\text{ }\Omega \mathrm{.}\)

Thus, the equivalent resistance is \(2\text{ }\Omega\).

Q4 FREE PREVIEW
PYQ

A wire of resistance \(9\text{ }\Omega\) is bent into the shape of an equilateral triangle. What is the equivalent resistance between any two vertices of the triangle?

(Shift I Memory Based)

a

\(1\text{ }\Omega\)

b

\(2\text{ }\Omega\)

c

\(3\text{ }\Omega\)

d

\(4\text{ }\Omega\)

✓ Correct answer: b)

\(2\text{ }\Omega\)

Explanation
  • Total resistance of the wire: \({R}_{\text{total}}=9\text{ }\Omega\)
  • Resistance of each side: \({R}_{\text{side}}=\frac{{R}_{\text{total}}}{3}=3\text{ }\Omega\)
  • Between any two vertices, there are two paths:
    1. Direct resistance \({R}_{1}=3\text{ }\Omega\).
    2. The other two sides (\({R}_{2}\)) add up: \({R}_{2}=6\text{ }\Omega\)
  • These are in parallel: \({R}_{\text{eq}}=\frac{{R}_{1}{R}_{2}}{{R}_{1}+{R}_{2}}=\frac{(3)(6)}{3+6}=2\text{ }\Omega \mathrm{.}\)

Thus, the equivalent resistance is \(2\text{ }\Omega\).

Q5 FREE PREVIEW
PYQ

Wheatstone bridge principle is used to measure the specific resistance \(\left(S_1\right)\) of given wire, having length \(L\), radius \(r\). If \(X\) is the resistance of wire, then specific resistance is ; \(S_1=X\left(\frac{\pi r^2}{L}\right)\). If the length of the wire gets doubled then the value of specific resistance will be :

[JEE Main 2024, 27 Jan (Shift 2)]

a

\(2 S_1\)

b

\(\frac{ S _1}{2}\)

c

\(S _1\)

d

\(\frac{S_1}{4}\)

✓ Correct answer: c)

\(S _1\)

Explanation

As specific resistance does not depends on dimension of wire so, it will not change.

Q6
PYQ

Wheatstone bridge principle is used to measure the specific resistance \(\left(S_1\right)\) of given wire, having length \(L\), radius \(r\). If \(X\) is the resistance of wire, then specific resistance is ; \(S_1=X\left(\frac{\pi r^2}{L}\right)\). If the length of the wire gets doubled then the value of specific resistance will be :

[JEE Main 2024, 27 Jan (Shift 2)]

a

\(2 S_1\)

b

\(\frac{ S _1}{2}\)

c

\(S _1\)

d

\(\frac{S_1}{4}\)

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Q7
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Statement I: When non-ideal batteries are connected in parallel, the resultant EMF is less than either of the batteries.

Statement II: When non-ideal batteries are connected in parallel, the resultant resistance of their internal resistances is smaller than either of the individual resistances.

Choose the correct option which is given below:(JEE Mains - 21 Jan 2025 - Shift I Memory Based)

a

Statement I is true and Statement II is false.

b

Statement I is false and Statement II is true.

c

Both the Statements are true.

d

Both the Statements are false.

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Q8
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In a metre-bridge when a resistance in the left gap is \(2 \Omega\) and unknown resistance in the right gap, the balance length is found to be \(40 cm\). On shunting the unknown resistance with \(2 \Omega\), the balance length changes by:

StartFragment [1-Feb.-2024_JEE Main (Shift-II)]EndFragment

a

20 cm

b

62.5 cm

c

22.5 cm

d

65 cm

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Q9
PYQ

Given below are two statements :
Statement-I: The equivalent emf of two non-ideal batteries connected in parallel is smaller than either of the two emfs.
Statement-II : The equivalent internal resistance of two non-ideal batteries connected in parallel is smaller than the internal resistance of either of the two batteries.
In the light of the above statements, choose the correct answer from the options given below.

a

Both Statement-I and Statement-II are true

b

Both Statement-I and Statement-II are false

c

Statement-I is true but Statement-II is false

d

Statement-I is false but Statement-II is true

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Q10
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Wheatstone bridge principle is used to measure the specific resistance \(\left(S_1\right)\) of given wire, having length \(L\), radius \(r\). If \(X\) is the resistance of wire, then specific resistance is ; \(S_1=X\left(\frac{\pi r^2}{L}\right)\). If the length of the wire gets doubled then the value of specific resistance will be :

a

\(2 S_1\)

b

\(\frac{ S _1}{2}\)

c

\(S _1\)

d

\(\frac{S_1}{4}\)

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Q11
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A motor operating on 100 V draws a current of 1 A. If the efficiency of the motor is 91.6%, then the loss of power in units of cal/s is

[JEE Main 2025, 3 Apr (Shift 2)]

a

\(4\)

b

\(8.4\)

c

\(2\)

d

\(6.2\)

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Q12
PYQ

Given below are two statements :
Statement-I: The equivalent emf of two nonideal batteries connected in parallel is smaller than either of the two emis.
Statement-II : The equivalent internal resistance of two nonideal batteries connected in parallel is smaller than the internal resistance of either of the two batteries.
In the light of the above statements, choose the correct answer from the options given below.

[JEE Main 2025, 22 Jan (Shift 1)]

a

Both Statement-I and Statement-II are true

b

Both Statement-I and Statement-II are false

c

Statement-I is true but Statement-II is false

d

Statement-I is false but Statement-II is true

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Q13
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Current passing through a wire as function of time is given as I(t) = 0.02t + 0.01 A. The charge that will flow through the wire from t = 1s to t = 2s is :

[JEE Main 2025, 4 Apr (Shift 1)]

a

0.06 C

b

0.02 C

c

0.07 C

d

0.04 C

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Q14
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The electric current through a wire varies with time as \(\mathrm{I}=\mathrm{I}_{0}+\beta \mathrm{t}\), where \(\mathrm{I}_{0}=20 \mathrm{~A}\) and \(\beta=3 \mathrm{~A} / \mathrm{s}\). The amount of electric charge crossed through a section of the wire in \(20 \mathrm{~s}\) is :

[JEE Main 2024, 29 Jan (Shift 1)]

a

\(800 \mathrm{C}\)

b

\(1600 \mathrm{C}\)

c

\(80 \mathrm{C}\)

d

\(1000 \mathrm{C}\)

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Q15
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The electric current through a wire varies with time as \(\mathrm{I}=\mathrm{I}_{0}+\beta \mathrm{t}\), where \(\mathrm{I}_{0}=20 \mathrm{~A}\) and \(\beta=3 \mathrm{~A} / \mathrm{s}\). The amount of electric charge crossed through a section of the wire in \(20 \mathrm{~s}\) is :

[JEE Main 2024, 29 Jan (Shift 1)]

a

\(800 \mathrm{C}\)

b

\(1600 \mathrm{C}\)

c

\(80 \mathrm{C}\)

d

\(1000 \mathrm{C}\)

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Q16
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Two resistors of \(200\Omega\) and \(400\Omega\) are connected in series with a battery of 100 V . A bulb rated at 200 V, 100 W is connected across the \(400\Omega\) resistance. The potential drop across the bulb is _________ V.

[02 April, 2026 (Shift-2)]

a

25

b

50

c

66.6

d

100

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Q17
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Statement I: When non-ideal batteries are connected in parallel, the resultant EMF is less than either of the batteries.

Statement II: When non-ideal batteries are connected in parallel, the resultant resistance of their internal resistances is smaller than either of the individual resistances.

Choose the correct option which is given below:(JEE Mains - 21 Jan 2025 - Shift I Memory Based)

a

Statement I is true and Statement II is false.

b

Statement I is false and Statement II is true.

c

Both the Statements are true.

d

Both the Statements are false.

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Q18
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A galvanometer having a coil of resistance \(30\Omega\) need 20 mA of current for full-scale deflection. If a maximum current of 3 A is to be measured using this galvanometer, the resistance of the shunt to be added to the galvanometer should be \(\frac{30}{X}\Omega\), where\(X\) is

[JEE Main 2025, 23 Jan (Shift 2)]

a

149

b

596

c

298

d

447

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Q19
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Two conductors have the same resistances at \(0^{\circ} \mathrm{C}\) but their temperature coefficients of resistance are \({\alpha }_{1}\)and \({\alpha }_{2}\). The respective temperature coefficients for their series and parallel combinations are :

a

\(\frac{\alpha_1+\alpha_2}{2}, \frac{\alpha_1+\alpha_2}{2}\)

b

\(\alpha_1+\alpha_2, \frac{\alpha_1+\alpha_2}{2}\)

c

\(\alpha_1+\alpha_2, \frac{\alpha_1 \alpha_2}{\alpha_1+\alpha_2}\)

d

\(\frac{\alpha_1+\alpha_2}{2}, \alpha_1+\alpha_2\)

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Q20
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A wire of resistance \(R\) and length \(L\) is cut into 5 equal parts. If these parts are joined parallely, then resultant resistance will be :

a

\(25 R\)

b

\(5 R\)

c

\(\frac{1}{25} R\)

d

\(\frac{1}{5} R\)

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Q21
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There are ‘n’ number of identical electric bulbs, each is designed to draw a power p independently from the mains supply. They are now joined in series across the main supply. The total power drawn by the combination is :

[JEE Main 2025, 4 Apr (Shift 2)]

a

\(\mathrm{np}\)

b

\(\frac{\mathrm{p}}{{\mathrm{n}}^{2}}\)

c

\(\frac{\mathrm{p}}{\mathrm{n}}\)

d

\(\mathrm{p}\)

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Q22
PYQ

A wire of resistance \(R\) and length \(L\) is cut into 5 equal parts. If these parts are joined parallely, then resultant resistance will be :

a

\(25 R\)

b

\(5 R\)

c

\(\frac{1}{25} R\)

d

\(\frac{1}{5} R\)

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Q23
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A moving coil galvanometer with coil resistance \(G=30\text{ }\Omega\), shows full-scale deflection when the current through it is \(20\text{ }\text{mA}\). The galvanometer is converted to an ammeter of range \(3\text{ }\text{A}\) by using a shunt resistance \(S\). The resistance \(S\) is:

(Shift - II Memory Based)

a

\(0.2\text{ }\Omega\)

b

\(2\text{ }\Omega\)

c

\(0.8\text{ }\Omega\)

d

\(1.2\text{ }\Omega\)

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Q24
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A galvanometer having a coil of resistance \(30\Omega\) need 20 mA of current for full-scale deflection. If a maximum current of 3 A is to be measured using this galvanometer, the resistance of the shunt to be added to the galvanometer should be \(\frac{30}{X}\Omega\), where\(X\) is

[JEE Main 2025, 23 Jan (Shift 2)]

a

149

b

596

c

298

d

447

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Q25
PYQ

A moving coil galvanometer with coil resistance \(G=30\text{ }\Omega\), shows full-scale deflection when the current through it is \(20\text{ }\text{mA}\). The galvanometer is converted to an ammeter of range \(3\text{ }\text{A}\) by using a shunt resistance \(S\). The resistance \(S\) is:

(Shift - II Memory Based)

a

\(0.2\text{ }\Omega\)

b

\(2\text{ }\Omega\)

c

\(0.8\text{ }\Omega\)

d

\(1.2\text{ }\Omega\)

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Q26
PYQ

A voltmeter with internal resistance of x \(\Omega\) can be used to measure upto 20 V. In order to increase its measuring range to 30 V , the required modification is to______.

[04 April, 2026 (Shift-I)]

a

connect resistor of \(\frac{x}{2}\)\(\Omega\) , in series with voltmeter.

b

connect resistor of \(\frac{x}{2}\)\(\Omega\), in parallel to voltmeter.

c

connect a resistor of x \(\Omega\) in series with voltmeter.

d

connect resistor of 2 x \(\Omega\) in parallel to voltmeter.

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Q27
PYQ

With the help of a potentiometer, we can determine the value of emf of a given cell. The sensitivity of the potentiometer
A. is directly proportional to the length of the potentiometer wire

B. is directly proportional to the potential gradient of the wire
C. is inversely proportional to the potential gradient of the wire
D. is inversely proportional to the length of the potentiometer wire

Choose the correct option for the above statements:

[JEE Main 2023, 29 Jan (Shift 2)]

a

B and D only

b

A and C only

c

A only

d

C only

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Q28
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What equal length of an iron wire and a copper-nickel alloy wire, each of 2 mm diameter connected parallel to give an equivalent resistance of \(3\Omega\) ? (Given resistivities of iron and copper-nickel alloy wire are \(12\mathrm{μΩ}\mathrm{cm}\) and \(51\mathrm{μΩ}\mathrm{cm}\) respectively)

[JEE Main 2021, 26 Aug (Shift 1)]

a

\(110m\)

b

\(90m\)

c

\(82m\)

d

\(97m\)

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Q29
PYQ

Ratio of thermal energy released in two resistors R and 3R connected in parallel in an electric circuit is :

[JEE Main 2023, 29 Jan (Shift 1)]

a

3: 1

b

1: 1

c

1: 3

d

1: 27

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Q30
PYQ

A wire of \(1\Omega\) has a length of \(1\mathrm{m}\). It is stretched till its length increases by \(25\%\). The percentage change in resistance to the nearest integer is:

[JEE Main 2021, 26 Feb (Shift 2)]

a

\(56\%\)

b

\(76\%\)

c

\(12.5\%\)

d

\(25\%\)

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Q31
PYQ

The solids which have the negative temperature coefficient of resistance are:

a

metals

b

insulators only

c

semiconductors only

d

insulators and semiconductors.

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Q32
PYQ

The resistance of a conductor at \(15^\circ C\) is \(16\Omega\) and at \(100^\circ C\) is \(20\Omega\). What will be the temperature coefficient of resistance of the conductor ?

[JEE Main 2021, 27 Jul (Shift 2)]

a

\(0.003^\circ {C}^{-1}\)

b

\(0.042^\circ {C}^{-1}\)

c

\(0.033^\circ {C}^{-1}\)

d

\(0.010^\circ {C}^{-1}\)

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Q33
PYQ

A wire of a certain material is stretched slowly by ten per cent. Its new resistance and specific resistance become respectively:

a

\(1.2\) times, \(1.3\) times

b

\(1.21\) times, same

c

both remain the same

d

\(1.1\) times, \(1.1\) times

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Q34
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What equal length of an iron wire and a copper-nickel alloy wire, each of 2 mm diameter connected parallel to give an equivalent resistance of \(3\Omega\) ? (Given resistivities of iron and copper-nickel alloy wire are \(12\mu \Omega cm\) and \(51\mu \Omega cm\) respectively)

[JEE Main 2021, 26 Aug (Shift 1)]

a

\(110m\)

b

\(90m\)

c

\(82m\)

d

\(97m\)

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Q35
PYQ

A capacitor is connected to a 20V battery through a resistance of \(10\Omega\). It is found that the potential difference across the capacitor rises to 2V in \(1\mu s\). The capacitance of the capacitor is ______ \(\mu F\). Given \(\ln \left(\frac{10}{9}\right)=0.105\)

[JEE Main 2021, 1 Sep (Shift 2)]

a

1.85

b

0.95

c

0.105

d

9.52

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Q36
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In the experiment of Ohm's law, a potential difference of \(5.0\mathrm{V}\) is applied across the end of a conductor of length \(10.0\mathrm{cm}\) and diameter of \(5.00\mathrm{mm}\). The measured current in the conductor is \(2.00\mathrm{A}\). The maximum permissible percentage error in the resistivity of the conductor is:

[JEE Main 2021, 18 Mar (Shift 1)]

a

3.9

b

8.4

c

3.0

d

7.5

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Q37
PYQ

Two identical heater filaments are connected first in parallel and then in series. At the same applied voltage, the ratio of heat produced in same time for parallel to series will be:

[JEE Main 2023, 11 Apr (Shift 1)]

a

4: 1

b

2: 1

c

1: 2

d

1: 4

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Q38
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Given below are two statements: One is labelled as Assertion \(A\) and the other is labelled as Reason \(R\).
Assertion \(A\) : For measuring the potential difference across a resistance of \(600 \Omega\), the voltmeter with resistance \(1000 \Omega\), will be preferred over voltmeter with resistance \(4000 \Omega\).
Reason \(R\) : Voltmeter with higher resistance will draw smaller current than voltmeter with lower resistance.
In the light of the above statements, choose the most appropriate answer from the options given below.

[JEE Main 2023, 1 Feb (Shift 2)]

a

\(A\) is not correct but \(R\) is correct

b

Both \(A\) and \(R\) are correct and \(R\) is the correct explanation of \(A\)

c

Both \(A\) and \(R\) are correct but \(R\) is not the correct explanation of \(A\)

d

\(A\) is correct but \(R\) is not correct.

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Q39
PYQ

The H amount of thermal energy is developed by a resistor in 10s when a current of 4A is passed through it. If the current is increased to 16A the thermal energy developed by the resistor in 10s will be:

[JEE Main 2023, 31 Jan (Shift 2)]

a

H

b

16H

c

\(\frac{H}{4}\)

d

4H

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Q40
PYQ

Consider a galvanometer shunted with \( 5 \Omega \) resistance and \( 2 \% \) of current passes through it. What is the resistance of the given galvanometer?

[JEE Main 2021, 31 Aug (Shift 1)]

a

\( 300 \ \Omega \)

b

\( 344 \ \Omega \)

c

\( 245 \ \Omega \)

d

\( 226 \ \Omega \)

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Q41
PYQ

A uniform metallic wire carries a current 2A, when 3.4 V battery is connected across it. The mass of uniform metallic wire is 8.92 × 10-3kg, density is 8.92 × 103 kg/m3 and resistivity is 1.7 × 10-8 \(\Omega\)-m . The length of wire is :

[JEE Main 2023, 25 Jan (Shift 1)]

a

l = 6.8 m

b

l = 10 m

c

l = 5 m

d

l = 100 m

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Q42
PYQ

A current of 5 A is passing through a non-linear magnesium wire of cross - section 0.04m2. At every point the direction of current density is at an angle of 60° with unit vector of area of cross -section. The magnitude of electric field at every point of the conductor is : (Resistivity of magnesium \(\rho =44\times {10}^{-8}\Omega m\))

a

\(11\times {10}^{-7}V/m\)

b

\(11\times {10}^{-2}V/m\)

c

\(11\times {10}^{-5}V/m\)

d

\(11\times {10}^{-3}V/m\)

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Q43
PYQ

A current of 10 A exists in a wire of cross-sectional area of \(5m{m}^{2}\) with a drift velocity of \(2\times {10}^{-3}m{s}^{-1}\). The number of free electrons in each cubic meter of the wire

a

\(2\times {10}^{25}\)

b

\(1\times {10}^{23}\)

c

\(2\times {10}^{6}\)

d

\(625\times {10}^{25}\)

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Q44
PYQ

If you are provided a set of resistances \(2\Omega ,4\Omega ,6\Omega\) and \(8\Omega\). Connect these resistances so as to obtain an equivalent resistance of \(\frac{46}{3}\Omega\).

[JEE Main 2021, 26 Aug (Shift 2)]

a

\(4\Omega\)and \(6\Omega\) are in parallel with \(2\Omega\) and \(8\Omega\) in series

b

\(6\Omega\) and \(8\Omega\) are in parallel with \(2\Omega\) and \(4\Omega\) in series.

c

\(2\Omega\) and \(4\Omega\) are in parallel with \(6\Omega\) and \(8\Omega\) in series.

d

\(2\Omega\) and \(6\Omega\) are in parallel with \(4\Omega\) and \(8\Omega\) in series.

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Q45
PYQ

The resistance of platinum wire at \(0^{\circ} \mathrm{C}\) is \(2 \Omega\) and 6.8 \(\Omega\) at \(80^{\circ} \mathrm{C}\). The temperature coefficient of resistance of the wire is :

[NEET 2023]

a

\(3\times {10}^{-3}{{}^{∘}\mathrm{C}}^{-1}\)

b

\(3\times {10}^{-2}{{}^{∘}\mathrm{C}}^{-1}\)

c

\(3\times {10}^{-1}{{}^{∘}\mathrm{C}}^{-1}\)

d

\(3\times {10}^{-4}{{}^{∘}\mathrm{C}}^{-1}\)

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Q46
PYQ

The charge flowing in a conductor changes with time as \(\mathbf{Q}(\mathbf{t})=\boldsymbol{\alpha t}-\boldsymbol{\beta} \mathbf{t}^{\mathbf{2}}+\boldsymbol{\gamma} \mathbf{t}^{\mathbf{3}}\). Where \(\boldsymbol{\alpha}, \boldsymbol{\beta}\) and \(\boldsymbol{\gamma}\) are constants. Minimum value of current is :

a

\(\alpha -\frac{3{\beta }^{2}}{\tau }\)

b

\(\alpha -\frac{{\gamma }^{2}}{3\beta }\)

c

\(\beta -\frac{{\alpha }^{2}}{3\gamma }\)

d

\(\alpha -\frac{{\beta }^{2}}{3\gamma }\)

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Q47
PYQ

Due to cold weather a \(1 m\) water pipe of cross-sectional area \(1 cm ^2\) is filled with ice at \(-10{ }^{\circ} C\). Resistance heating is used to melt the ice. Current of \(0.5 A\) is passed through \(4 k \Omega\) resistance. Assuming that all the heat produced is used for melting, what is the minimum time required?(Given latent heat of fusion ice \(=3.33 \times 10^5 J kg ^{-1}\), specific heat of ice \(=2 \times 10^3 J kg ^{-1}\) and density of ice \(\left.=10^3 kg / m ^3\right)\)

[JEE Main 2021, 1 Sep (Shift 2)]

a

\(0.353 s\)

b

\(3.53 s\)

c

\(70.6 s\)

d

\(35.3 s\)

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Q48
PYQ

The H amount of thermal energy is developed by a resistor in 10s when a current of 4A is passed through it. If the current is increased to 16A. the thermal energy developed by the resistor in 10s will be:

[JEE Main 2023, 31 Jan (Shift 2)]

a

\(H\)

b

\(16H\)

c

\(\frac{H}{4}\)

d

\(4H\)

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Q49
PYQ

In a metallic conductor, under the effect of applied electric field ,the free electrons of the conductor

[JEE Main 2023, 10 Apr (Shift 2)]

a

drift from higher potential to lower potential

b

move in the curved paths from lower potential to higher potential

c

move with the uniform velocity throughout from lower potential to higher potential

d

move in the straight line paths in the same direction

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Q50
PYQ

The material filled between the plates of a parallel plate capacitor has resistivity \(200\mathrm{Ωm}\). The value of capacitance of the capacitor is \(2\mathrm{pF}\). If a potential difference of \(40\mathrm{V}\) is applied across the plates of the capacitor, then the value of leakage current flowing out of the capacitor is : (given the value of relative permittivity of material is 50 )

a

\(0.9\mu \mathrm{A}\)

b

\(9.0\mathrm{mA}\)

c

\(9.0\mu \mathrm{A}\)

d

\(0.9\mathrm{mA}\)

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Q51
PYQ

The number of turns of the coil of a moving coil galvanometer is increased in order to increase current sensitivity by 50%. The percentage change in voltage sensitivity of the galvanometer will be:

[JEE Main 2023, 31 Jan (Shift 2)]

a

100%

b

50%

c

75%

d

0%

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