If the coordinates at one end of a diameter of the circle $x^2+y^2-8 x-4 y+c=0$ are $(-3,2)$, then the coordinates at the other end are

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If the coordinates at one end of a diameter of the circle \(x^2+y^2-8 x-4 y+c=0\) are \((-3,2)\), then the coordinates a…