If \(\ \mathbf{x}=\frac{1-t^2}{1+t^2} \) and \(\mathbf{y}=\frac{2 t}{1+t^2} \), then \(\ \frac{d y}{d x} \) is equal to …
Q1
If \(\ \mathbf{x}=\frac{1-t^2}{1+t^2} \) and \(\mathbf{y}=\frac{2 t}{1+t^2} \), then \(\ \frac{d y}{d x} \) is equal to :
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