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If the time period of a two meter long simple pendulum is \(2 s\), the acceleration due to gravity at the place where pe…

Q1

If the time period of a two meter long simple pendulum is \(2 s\), the acceleration due to gravity at the place where pendulum is executing S.H.M. is:

[JEE Main 2021, 25 Feb (Shift 1)]]

a

\(9.8m{s}^{-2}\)

b

\(16m{s}^{-2}\)

c

\(2{\pi }^{2}m{s}^{-2}\)

d

\({\pi }^{2}m{s}^{-2}\)

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