The derivation of \(\tan ^{-1}\left(\frac{\sqrt{1+x^2}-1}{x}\right)\) with respect to \(\tan ^{-1}\left(\frac{2 x \sqrt{…
Q1
PYQThe derivation of \(\tan ^{-1}\left(\frac{\sqrt{1+x^2}-1}{x}\right)\) with respect to \(\tan ^{-1}\left(\frac{2 x \sqrt{1-x^2}}{1-2 x^2}\right)\) at \(x=\frac{1}{2}\) is:
[JEE Main 2020, 5 Sep (Shift 2)]
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