The derivation of $\tan ^{-1}\left(\frac{\sqrt{1+x^2}-1}{x}\right)$ with respect to $\tan ^{-1}\left(\frac{2 x \sqrt{1-x^2}}{1-2 x^2}\right)$ at $x=\frac{1}{2}$ is: [JEE Main 2020, 5 Sep (Shift 2)]

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The derivation of \(\tan ^{-1}\left(\frac{\sqrt{1+x^2}-1}{x}\right)\) with respect to \(\tan ^{-1}\left(\frac{2 x \sqrt{…

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