A metallic surface is illuminated with radiation of wavelength \(\lambda\), the stopping potential is \(V_{0^*}\) If the…
Q1
A metallic surface is illuminated with radiation of wavelength \(\lambda\), the stopping potential is \(V_{0^*}\) If the same surface is illuminated with radiation of wavelength \(2 \lambda\), the stopping potential becomes \(\frac{V_o}{4}\). The threshold wavelength for this metallic surface will be
[JEE Main 2023, 11 Apr (Shift 1)]
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