YESPYQ Start Practice
🛠️ JEE🧪 Chemistry

For the reaction, \(2 \mathrm{H}_2(\mathrm{~g})+2 \mathrm{NO}(\mathrm{g}) \rightarrow \mathrm{N}_2(\mathrm{~g})+2 \mathr…

Q1

For the reaction, \(2 \mathrm{H}_2(\mathrm{~g})+2 \mathrm{NO}(\mathrm{g}) \rightarrow \mathrm{N}_2(\mathrm{~g})+2 \mathrm{H}_2 \mathrm{O}(\mathrm{g})\); the observed rate expression is, rate \(=\mathrm{k}_{\mathrm{f}}[\mathrm{NO}]^2\left[\mathrm{H}_2\right]\).
The rate expression for the reverse reaction is
[JEE Main 2020, 7 Jan (Shift 2)]

a

\(\mathrm{k}_b\left[\mathrm{~N}_2\right]\left[\mathrm{H}_2 \mathrm{O}\right]\)

b

\(\mathrm{k}_b\left[\mathrm{~N}_2\right]\left[\mathrm{H}_2 \mathrm{O}\right]^2 /[\mathrm{NO}]\)

c

\(\mathrm{k}_{\mathrm{b}}\left[\mathrm{N}_2\right]\left[\mathrm{H}_2 \mathrm{O}\right]^2 /\left[\mathrm{H}_2\right]\)

d

\(\mathrm{k}_{\mathrm{b}}\left[\mathrm{N}_2\right]\left[\mathrm{H}_2 \mathrm{O}\right]^2\)

🔒
Answer & explanation — PYQ Pass

Options are free to see. Unlock the correct answer and full explanation with Pass.

Unlock · ₹149
← Previous questionNext question →

Practice more JEE Chemistry PYQs

See every question on Chemical Kinetics, or browse the full JEE question bank.

See all questions on Chemical Kinetics →