If $ f^{\prime}(x)=\tan ^{-1}(\sec x+\tan x),-\frac{\pi}{2}

Question

If $ f^{\prime}(x)=\tan ^{-1}(\sec x+\tan x),-\frac{\pi}{2}<x<\frac{\pi}{2} $, and $ f(0)=0 $, then $ f(1) $ is equal to : [JEE Main 2020, 9 Jan (Shift 1)]

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If \( f^{\prime}(x)=\tan ^{-1}(\sec x+\tan x),-\frac{\pi}{2}<x<\frac{\pi}{2} \), and \( f(0)=0 \), then \( f(1) \)…

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If \( f^{\prime}(x)=\tan ^{-1}(\sec x+\tan x),-\frac{\pi}{2}<x<\frac{\pi}{2} \), and \( f(0)=0 \), then \( f(1) \)…