If the lines \(\frac{x-1}{1}=\frac{y-2}{2}=\frac{z+3}{1}\) and \(\frac{x-a}{2}=\frac{y+2}{3}=\frac{z-3}{1}\) intersects …

If the lines \(\frac{x-1}{1}=\frac{y-2}{2}=\frac{z+3}{1}\) and \(\frac{x-a}{2}=\frac{y+2}{3}=\frac{z-3}{1}\) intersects at the point \(P\), then the distance of the point \(P\) from the plane \(z=a\) is:

[JEE Main 2023, 29 Jan (Shift 2)]