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Three Dimensional Geometry

157 JEE Maths previous year questions on Three Dimensional Geometry — options free on every question; 16 include the answer & explanation free, the rest unlock with PYQ Pass.

Q1 FREE PREVIEW
PYQ

Let the line L be \(\frac{x-1}{1}=\frac{y-4}{3}=\frac{z-7}{5}\) and foot of perpendicular from (1,-2,-1) to L is \((\alpha ,\beta ,\gamma )\), then \(\alpha +\beta +\gamma\) is :

a

\(\frac{-69}{35}\)

b

\(\frac{102}{35}\)

c

\(\frac{69}{35}\)

d

\(\frac{-102}{35}\)

✓ Correct answer: d)

\(\frac{-102}{35}\)

Explanation

\(\frac{x-1}{1}=\frac{y-4}{3}-\frac{z-7}{5}=\lambda (l\mathrm{et})\\ B(\lambda +1,3\lambda +4,5\lambda +7)\\ DR's\text{of}AB=⟨\lambda ,3\lambda +6,5\lambda +8⟩\\ Now,\lambda +9\lambda +18+25\lambda +40=0\\ \lambda =\frac{-58}{35}\\ B=(\frac{-58}{35}+1,3\left(\frac{-58}{35}\right)+4,5\left(\frac{-58}{35}\right)+7)\\ =\left(\frac{-23}{35},\frac{-34}{35},\frac{-45}{35}\right)=\left(\alpha ,\beta ,\gamma \right)\\ \mathrm{Now},\alpha +\beta +\gamma =\frac{-23-34-45}{35}=\frac{-102}{35}\\ \\\)

Q2 FREE PREVIEW
PYQ

The square of the distance of the point of intersection of the lines \(\vec{r}=(\hat{i}+\hat{j}-\hat{k})+\lambda(a \hat{i}-\hat{j}), a \neq 0\) and \(\vec{r}=(4 \hat{i}-\hat{k})+\mu(2 \hat{i}+a \hat{k})\) from the origin is:


[JEE Main 2026, 5 Apr (Shift 1)]

a

\(5\)

b

\(10\)

c

\(17\)

d

\(26\)

✓ Correct answer: c)

\(17\)

Explanation

Let the point of intersection be \(A\)

\( \therefore A(1+\lambda a, 1-\lambda,-1) \equiv(4+2 \mu, 0,-1+\mu a) \)
\( \therefore 1-\lambda=0 \Rightarrow \lambda=1 \)
\( \mu a=0 \Rightarrow \mu=0 \ (\because a \neq 0) \)
\( 1+\lambda a=4+2 \mu \Rightarrow 2 \mu-a=-3\)
\( \Rightarrow a=3 \)
\( \therefore A(4,0,-1) \)
\( \therefore d^2=(\sqrt{16+1})^2=17\)

Q3 FREE PREVIEW
PYQ

The perpendicular distance, of the line \(\frac{x-1}{2}=\frac{y+2}{-1}=\frac{z+3}{2}\) from the point \(P(2,-10,1)\), is:

[JEE Main 2025, 22 Jan (Shift 2)]

a

6

b

\(5\sqrt{2}\)

c

\(3\sqrt{5}\)

d

\(4\sqrt{3}\)

✓ Correct answer: c)

\(3\sqrt{5}\)

Explanation

\(\frac{x-1}{2}=\frac{y+2}{-1}=\frac{z+3}{2}=\lambda \\ \text{Let}A\text{is the point on the line,}\\ A(2\lambda +1,-\lambda -2,2\lambda -3)\text{and}P(2,-10,1)\\ ∵\vec{\mathrm{PA}}\cdot \vec{\mathrm{n}}=0\\ \Rightarrow (2\lambda -1)2+(-\lambda +8)(-1)+(2\lambda -4)2=0\\ \Rightarrow 4\lambda -2+\lambda -8+4\lambda -8=0\\ \Rightarrow 9\lambda -18=0\Rightarrow \lambda =2\\ ∴\mathrm{A}(5,-4,1)\\ ∴\mathrm{AP}=\sqrt{{3}^{2}+{6}^{2}+{0}^{2}}=\sqrt{45}=3\sqrt{5}\)

Q4 FREE PREVIEW
PYQ

The shortest distance between the lines\(\frac{x-4}{1}=\frac{y-3}{2}=\frac{z-2}{-3}\) and \(\frac{x+2}{2}=\frac{y-6}{4}=\frac{z-5}{-5}\) is:

[JEE Main 2026, 6 Apr (Shift 2)]

a

\(\frac{5\sqrt{6}}{6}\)

b

\(2\sqrt{5}\)

c

\(3\sqrt{5}\)

d

\(4\sqrt{5}\)

✓ Correct answer: c)

\(3\sqrt{5}\)

Explanation

Shortest distance \(=\frac{\left|\left(\overrightarrow{a_2}-\overrightarrow{a_1}\right) \cdot\left(\overrightarrow{b_1} \times \overrightarrow{b_2}\right)\right|}{\left|\overrightarrow{b_1} \times \overrightarrow{b_2}\right|}\)

\(\overrightarrow{b_1} \times \overrightarrow{b_2}=\left|\begin{array}{ccc}\hat{i} & \hat{j} & \hat{k} \\ 1 & 2 & -3 \\ 2 & 4 & -5\end{array}\right|\)

\(=\hat{i}(-10+12)-\hat{j}(-5+6)+\hat{k}(4-4)\)

\(=2 \hat{i}-\hat{j}+0 \hat{k}\)

\(\left|\overrightarrow{b_1} \times \overrightarrow{b_2}\right|=\sqrt{2^2+(-1)^2+0^2}=\sqrt{5}\)

\(\overrightarrow{a_2}-\overrightarrow{a_1}=(-2-4) \hat{i}+(6-3) \hat{j}+(5-2) \hat{k}=-6 \hat{i}+3 \hat{j}+3 \hat{k}\)

\(\left(\overrightarrow{a_2}-\overrightarrow{a_1}\right) \cdot\left(\overrightarrow{b_1} \times \overrightarrow{b_2}\right)\)

\(=(-6 \hat{i}+3 \hat{j}+3 \hat{k})\cdot (2 \hat{i}-\hat{j}+0 \hat{k})=-15\)

Hence shortest distance

\(d=\frac{15}{\sqrt{5}}=3 \sqrt{5}\)

Q5 FREE PREVIEW
PYQ

Let \(L\), be the line \(\frac{x+1}{2}=\frac{y+1}{3}=\frac{z+3}{6}\) and let \(S\) be the set of all points \((a, b, c)\) on \(L\), whose distance from the line \(\frac{x+1}{2}=\frac{y+1}{3}=\frac{z−9}{0}\) along the line \(L\) is \(7\). Then \(\sum _{(a,\text{  }b,\text{  }c)\in S}(a+b+c)\) is equal

[JEE Main 2026, 22 Jan (Shift 2)]

a

40

b

34

c

28

d

6

✓ Correct answer: b)

34

Explanation

\(\frac{x+1}{2}=\frac{y+1}{3}=\frac{z+3}{6}=\lambda\)

\( x=2 \lambda-1, y=3 \lambda-1 \) & \(z=6 \lambda-3\)

\(\frac{x+1}{2}=\frac{y+1}{3}=\frac{z-9}{0}\)

\( x=2 \mu-1, y=3 \mu-1 \) & \(z=9\)

Let \(M\) is the point of intersection of both given lines

\(\Rightarrow 2\lambda −1=2\mu −1,3\lambda −1=3\mu −1,6\lambda −3=9\)

\(\Rightarrow \lambda =2=\mu\)

\(\Rightarrow \text{M }\left(3,5,9\right)\)

Now let point \(P\) be \(\left(2\text{ K}−1,3\text{ K}−1,6\text{ K}−3\right)\) on \(\text{L}\) such that \(\text{PM}=7\)

\(\Rightarrow \sqrt{{(2\text{K}−4)}^{2}+{(3\text{K}−6)}^{2}+{(6\text{K}−12)}^{2}}=7\)

\(\Rightarrow 49{\text{ K}}^{2}+196−196\text{K}=49\)

\(\Rightarrow {\text{K}}^{2}+4−4\text{K}=1\)

\(\Rightarrow {\text{K}}^{2}−4\text{K}+3=0\)

\(\Rightarrow \text{K}=1,3\)

So points are \(P\left(1,2,3\right)\) or \(P\left(5,8,15\right)\)

So sum of all co-ordinates of \(P = 34\)

Q6 FREE PREVIEW
PYQ

Let \(\vec{\mathrm{a}}=\hat{\mathrm{i}}+2\hat{\mathrm{j}}+\hat{\mathrm{k}}\text{ and }\vec{\mathrm{b}}=2\hat{\mathrm{i}}+7\hat{\mathrm{j}}+3\hat{\mathrm{k}}.\) Let \({\mathrm{L}}_{1}:\vec{\mathrm{r}}=(-\hat{\mathrm{i}}+2\hat{\mathrm{j}}+\hat{\mathrm{k}})+\lambda \vec{\mathrm{a}},\lambda \in \mathrm{R}\text{ and }\)\({L}_{2}:\vec{\mathrm{r}}=(\hat{\mathrm{j}}+\hat{\mathrm{k}})+\mu \vec{\mathrm{b}},\mu \in \mathrm{R}\) be two lines. If the line \(L_3\) passes through the point of intersection of \(L_1\) and \(L_2\), and is parallel to \(\vec{a}+\vec{b}\), then \(L_3\) passes through the point:

[JEE Main 2025, 29 Jan (Shift 1)]

a

\((8, 26, 12) \)

b

\((2, 8, 5) \)

c

\((-1, -1, 1) \)

d

\((5, 17, 4) \)

✓ Correct answer: a)

\((8, 26, 12) \)

Explanation

Given

\({L}_{1}:\vec{\mathrm{r}}=(-\hat{\mathrm{i}}+2\hat{\mathrm{j}}+\hat{\mathrm{k}})+\lambda (\hat{\mathrm{i}}+2\hat{\mathrm{j}}+\hat{\mathrm{k}})\\ \Rightarrow \vec{\mathrm{r}}=(\lambda -1)\hat{\mathrm{i}}+2(\lambda +1)\hat{\mathrm{j}}+(\lambda +1)\hat{\mathrm{k}}\)

Next,

\({L}_{2}:\vec{\mathrm{r}}=(\hat{\mathrm{j}}+\hat{\mathrm{k}})+\mu (2\hat{\mathrm{i}}+7\hat{\mathrm{j}}+3\hat{\mathrm{k}})\\ \Rightarrow \vec{\mathrm{r}}=2\mu \hat{\mathrm{i}}+(1+7\mu )\hat{\mathrm{j}}+(1+3\mu )\hat{\mathrm{k}}\)

for point of intersection of \({L}_{1}\text{and}{L}_{2}\)

\(\lambda -1=2\mu \text{and}2(\lambda +1)=1+7\mu \\ \text{On solving, }\lambda =3\text{ and }\mu =1\\ \Rightarrow \vec{\mathrm{a}}+\vec{\mathrm{b}}=3\hat{\mathrm{i}}+9\hat{\mathrm{j}}+4\hat{\mathrm{k}}\\ \text{hence, }\\ {\mathrm{L}}_{3}:\vec{\mathrm{r}}=2\hat{\mathrm{i}}+8\hat{\mathrm{j}}+4\hat{\mathrm{k}}+\alpha (3\hat{\mathrm{i}}+9\hat{\mathrm{j}}+4\hat{\mathrm{k}})\\ \text{from options, we can see}{\mathrm{L}}_{3}\mathrm{passes}\\ \mathrm{through}(8,26,12)\)

Q7 FREE PREVIEW
PYQ

Let the direction cosines of two lines satisfy the equations: \(4l+m-n=0\) and \(2mn+10nl+3lm=0\). Then the cosine of the acute angle between these lines is:

[JEE Main 2026, 23 Jan (Shift 1)]

a

\(\frac{20}{3\sqrt{38}}\)

b

\(\frac{10}{3\sqrt{38}}\)

c

\(\frac{10}{\sqrt{38}}\)

d

\(\frac{10}{7\sqrt{38}}\)

✓ Correct answer: b)

\(\frac{10}{3\sqrt{38}}\)

Explanation

Direction cosines of two lines satisfy the equation

\(4ℓ+m-n=0\\ \Rightarrow n=4ℓ+m...\left(1\right)\\ 2mn+10nℓ+3ℓm=0\\ \Rightarrow n\left(2m+10ℓ\right)+3ℓm=0...\left(2\right)\)

from eq. (1) and (2):

\(\Rightarrow (4ℓ+m)(2m+10ℓ)+3ℓm=0\\ \Rightarrow 8ℓm+40{ℓ}^{2}+2{m}^{2}+10ℓm+3ℓm=0\)

\(\Rightarrow 40{ℓ}^{2}+21ℓm+2{m}^{2}=0\\ \Rightarrow (8ℓ+m)(5ℓ+2m)=0\)

Case-1: \(8ℓ+m=0\Rightarrow m=-8ℓ\)
So direction ratio of \({L}_{1}\) is \(ℓ,-8ℓ,-4ℓ\)

Case-2: \(5ℓ+2m=0\Rightarrow m=\frac{-5}{2}ℓ\)
direction ratio of \({L}_{2}\) is \(ℓ,\frac{-5ℓ}{2},\frac{3ℓ}{2}\)

\(\cos \theta =\left|\frac{{ℓ}^{2}+20{ℓ}^{2}-6{ℓ}^{2}}{\sqrt{{ℓ}^{2}+64{ℓ}^{2}+16{ℓ}^{2}}\sqrt{{ℓ}^{2}+\frac{25{ℓ}^{2}}{4}+\frac{9{ℓ}^{2}}{4}}}\right|\\ =\frac{15{ℓ}^{2}}{\left(9ℓ\right)\frac{\sqrt{38}ℓ}{2}}=\frac{10}{3\sqrt{38}}\\ =\frac{10}{3\sqrt{38}}\)

Q8 FREE PREVIEW
PYQ

Let the values of \(\lambda\) for which the shortest distance between the lines \(\frac{x-1}{2}=\frac{y-2}{3}=\frac{z-3}{4}\) and \(\frac{x-\lambda }{3}=\frac{y-4}{4}=\frac{z-5}{5}\) is \(\frac{1}{\sqrt{6}}\) be \({\lambda }_{1}\) and \({\lambda }_{2}\). Then the radius of the circle passing through the points \((0,0),\left({\lambda }_{1},{\lambda }_{2}\right)\) and \(\left({\lambda }_{2},{\lambda }_{1}\right)\) is

[JEE Main 2025, 8 Apr (Shift 1)]

a

\(\frac{5\sqrt{2}}{3}\)

b

\(4\)

c

\(\frac{\sqrt{2}}{3}\)

d

\(3\)

✓ Correct answer: a)

\(\frac{5\sqrt{2}}{3}\)

Explanation

\(\Rightarrow \text{ }\vec{p}\text{ }\times \text{ }\vec{q}=\text{ }\left|\begin{matrix}\hat{i} & \hat{j} & \hat{k} \\ 2 & 3 & 4 \\ 3 & 4 & 5\end{matrix}\right|\text{ }=−\hat{i}+2\hat{j}-k\)

\(A\text{ }\equiv \text{ }\left(1,\text{  }2,\text{  }3\right)\text{  }B\text{ }\equiv \text{ }\left(\lambda ,\text{  }4,\text{  }5\right)\)

Shortest Distance

\(=\text{ }\left|\frac{\vec{AB}\text{ }⋅\text{ }\left(\vec{p}\text{ }\times \vec{q}\right)}{\left|\vec{p}\text{ }\times \text{ }\vec{q}\right|}\right|\text{ }.\frac{1}{\sqrt{6}}\)

\(=\text{ }\left|\frac{\left(\left(\lambda −1\right)\text{ }\hat{i}\text{ }−\text{ }2\hat{j}\text{ }+\text{ }2\hat{k}\right)\text{ }⋅\text{ }\left(−\hat{i}\text{ }+\text{ }2\hat{j}\text{ }−\text{ }\hat{k}\right)}{\sqrt{6}}\right|\)

\(\Rightarrow \text{ }\left|−\text{ }\lambda +1+4−2\right|=1\)

\(\Rightarrow \text{ }\left|\text{ }\lambda −3\right|=1\)

\(\Rightarrow \text{ }\lambda =3\text{ }\pm \text{ }1=\text{ }4\text{ },\text{  }2\text{ }\)

Radius of circle passing through points (0, 0), (4, 2) & (2, 4)

\(=\frac{abc}{4\Delta }\)

\(=\frac{\sqrt{20}\times \sqrt{20}\times \sqrt{8}}{4\times \frac{1}{2}\text{ }\left|\begin{matrix}1 & 1 & 1 \\ 0 & 4 & 2 \\ 0 & 2 & 4\end{matrix}\right|}\)

\(=\frac{20\times 2\sqrt{2}}{2\times 12}=\frac{5\sqrt{2}}{3}\)

Q9 FREE PREVIEW
PYQ

Let the acute angle bisector of the two planes \(x-2 y-2 z+1=0\) and \(2 x-3 y-6 z+1=0\) be the plane \(P\). Then which of the following points lies on \(P\) ?

a

\(\left(3,1,-\frac{1}{2}\right)\)

b

\(\left(-2,0,-\frac{1}{2}\right)\)

c

\((0,2,-4)\)

d

\((4,0,-2)\)

✓ Correct answer: b)

\(\left(-2,0,-\frac{1}{2}\right)\)

Explanation

\({P}_{1}:x-2y-2z+1=0\\ {P}_{2}:2x-3y-6z+1=0\\ \left|\frac{x-2y-2z+1}{\sqrt{1+4+4}}\right|=\left|\frac{2x-3y-6z+1}{\sqrt{{2}^{2}+{3}^{2}+{6}^{2}}}\right|\\ \frac{x-2y-2z+1}{3}=\pm \frac{2x-3y-6z+1}{7}\\ \text{ Since }{a}_{1}{a}_{2}+{b}_{1}{b}_{2}+{c}_{1}{c}_{2}=20>0\\ \text{∴Negative sign will give  acute bisector}\\ 7x-14y-14z+7=-[6x-9y-18z+3]\\ \Rightarrow 13x-23y-32z+10=0\\ \left(-2,0,-\frac{1}{2}\right)\text{ satisfy it. }\)

Q10 FREE PREVIEW
PYQ

\({\mathrm{L}}_{1}=\frac{x-1}{1}=\frac{y-2}{-1}=\frac{z-1}{2},{L}_{2}:\frac{x+1}{-1}=\frac{y-2}{2}=\frac{z}{1}\)

Let the line \({\mathrm{L}}_{3}\) passes through the point \((\alpha ,\beta ,\gamma )\) perpendicular to \({L}_{1}\&{L}_{2}\) and \({L}_{3}\) intersect line \({L}_{1}\) then \(|5\alpha -11\beta -8\gamma |\).

a

25

b

18

c

16

d

20

✓ Correct answer: a)

25

Explanation

\({\text{ L}}_{1}\text{: }\frac{x-1}{1}=\frac{y-2}{-1}=\frac{z-1}{2},{L}_{2}:\frac{x+1}{-1}=\frac{y-2}{2}=\frac{z}{1}\\ D'ratioof{L}_{1}\times {L}_{2}=\left|\begin{matrix}\hat{ı} & \hat{ȷ} & \hat{k} \\ 1 & -1 & 2 \\ -1 & 2 & 1\end{matrix}\right|=-5\hat{ı}-3\hat{ȷ}+\hat{k}\\ {L}_{3}:\frac{x-\alpha }{-5}=\frac{y-\beta }{-3}=\frac{z-\gamma }{1}=\mu \\ \left(5\mu +\alpha ,3\mu +\beta ,-\mu +\gamma \right)\\ Pat{L}_{1},\left(\lambda +1,-\lambda +2,2\lambda +1\right)\\ 5\mu +\alpha =\lambda +13\mu +\beta =-\lambda +2-\mu +\gamma =2\lambda +1\\ 5\mu -\lambda =1-\alpha 3\mu +\lambda =2-\beta \\ \mu =\frac{3-\alpha -\beta }{8}then\lambda =\frac{7+3\alpha -5\beta }{8}\\ -\left(\frac{3-\alpha -\beta }{8}\right)+\gamma =2\left(\frac{7+3\alpha -5\beta }{8}\right)+1\\ -3+\alpha +\beta +8\gamma =14+6\alpha -10\beta +8\\ \left|5\alpha -11\beta -8\gamma \right|=\left|-25\right|=25\)

Q11 FREE PREVIEW
PYQ

Let \(P Q R\) be a triangle with \(R(-1,4,2)\). Suppose \(M(2,1,2)\) is the mid point of \(\mathrm{PQ}\). The distance of the centroid of \(\triangle \mathrm{PQR}\) from the point of intersection of the lines \(\frac{x-2}{0}=\frac{y}{2}=\frac{z+3}{-1}\) and \(\frac{x-1}{1}=\frac{y+3}{-3}=\frac{z+1}{1}\) is

[JEE Main 2024, 29 Jan (Shift 1)]

a

\(69\)

b

\(\sqrt{69}\)

c

\(\sqrt{99}\)

d

\(9\)

✓ Correct answer: b)

\(\sqrt{69}\)

Explanation

G is centroid of \(\triangle PQR\)

\(∴G\equiv \left(\frac{2\times 2−1}{3},\frac{2\times 1+4}{3},\frac{2\times 2+2}{3}\right)\)

\(G\equiv (1,2,2)\)

Let \(x\) is the point of intersection of lines

\({l}_{1}:\frac{x−2}{0}=\frac{y}{2}=\frac{z+3}{−1}\)

\({k}_{2}:\frac{x−1}{1}=\frac{y+3}{−3}=\frac{z+1}{1},\text{ then }x\equiv (2,−6,0)\)

\(∴\)distance between \(G\) and \(x=\sqrt{69}\)

Q12 FREE PREVIEW
PYQ

Let \(P Q R\) be a triangle with \(R(-1,4,2)\). Suppose \(M(2,1,2)\) is the mid point of \(\mathrm{PQ}\). The distance of the centroid of \(\triangle \mathrm{PQR}\) from the point of intersection of the lines \(\frac{x-2}{0}=\frac{y}{2}=\frac{z+3}{-1}\) and \(\frac{x-1}{1}=\frac{y+3}{-3}=\frac{z+1}{1}\) is

[JEE Main 2024, 29 Jan (Shift 1)]

a

\(69\)

b

\(\sqrt{69}\)

c

\(\sqrt{99}\)

d

\(9\)

✓ Correct answer: b)

\(\sqrt{69}\)

Explanation

G is centroid of \(\triangle PQR\)

\(∴G\equiv \left(\frac{2\times 2−1}{3},\frac{2\times 1+4}{3},\frac{2\times 2+2}{3}\right)\)

\(G\equiv (1,2,2)\)

Let \(x\) is the point of intersection of lines

\({l}_{1}:\frac{x−2}{0}=\frac{y}{2}=\frac{z+3}{−1}\)

\({k}_{2}:\frac{x−1}{1}=\frac{y+3}{−3}=\frac{z+1}{1},\text{ then }x\equiv (2,−6,0)\)

\(∴\)distance between \(G\) and \(x=\sqrt{69}\)

Q13 FREE PREVIEW
PYQ

The perpendicular distance, of the line \(\frac{x-1}{2}=\frac{y+2}{-1}=\frac{z+3}{2}\) from the point \(P(2,-10,1)\), is:

[JEE Main 2025, 22 Jan (Shift 2)]

a

\(6\)

b

\(5\sqrt{2}\)

c

\(3\sqrt{5}\)

d

\(4\sqrt{3}\)

✓ Correct answer: c)

\(3\sqrt{5}\)

Explanation

Given \(P(2,-10,1)\)

\(\frac{x-1}{2}=\frac{y+2}{-1}=\frac{z+3}{2}=\lambda\)

Let \(A\) is the point on the line,

\(A\left(2\lambda +1,-\lambda -2,2\lambda -3\right)\)

\(∵\vec{\mathrm{PA}}\cdot \vec{\mathrm{n}}=0\\ \Rightarrow \left(2\lambda -1\right)2+\left(-\lambda +8\right)\left(-1\right)+\left(2\lambda -4\right)2=0\\ \Rightarrow 4\lambda -2+\lambda -8+4\lambda -8=0\\ \Rightarrow 9\lambda -18=0\Rightarrow \lambda =2\\ ∴\mathrm{A}\left(5,-4,1\right)\\ ∴\mathrm{AP}=\sqrt{{3}^{2}+{6}^{2}+{0}^{2}}=\sqrt{45}=3\sqrt{5}\)

Q14 FREE PREVIEW
PYQ

Let the image of the point \((1,0,7)\) in the line \(\frac{x}{1}=\frac{y-1}{2}=\frac{z-2}{3}\) be the point \((\alpha, \beta, \gamma)\). Then which one of the following points lies on the line passing through \((\alpha, \beta, \gamma)\) and making angles \(\frac{2 \pi}{3}\) and \(\frac{3 \pi}{4}\) with \(y\)-axis and \(z\)-axis respectively and an acute angle with \(x\)-axis?

a

\((3,-4,3+2 \sqrt{2})\)

b

\((3,4,3-2 \sqrt{2})\)

c

\((1,-2,1+\sqrt{2})\)

d

\((1,2,1-\sqrt{2})\)

✓ Correct answer: b)

\((3,4,3-2 \sqrt{2})\)

Explanation

Given point P(1,0,7).

Given line:

\(\frac{\left(x−1\right)}{1}=\frac{y}{\left(−3\right)}=\frac{\left(z−8\right)}{1}\)

A point on line is A(1,0,8).

Direction ratios of line = (1,−3,1).

Find foot of perpendicular H from P to line.

Using reflection formula:

\({P}^{'}=2H−P\)

After applying angle conditions given in question, required point obtained is the option corresponding to (B).

Q15 FREE PREVIEW
PYQ

Let the image of the point \((1,0,7)\) in the line \(\frac{x}{1}=\frac{y-1}{2}=\frac{z-2}{3}\) be the point \((\alpha, \beta, \gamma)\). Then which one of the following points lies on the line passing through \((\alpha, \beta, \gamma)\) and making angles \(\frac{2 \pi}{3}\) and \(\frac{3 \pi}{4}\) with \(y\)-axis and \(z\)-axis respectively and an acute angle with \(x\)-axis?

a

\((3,-4,3+2 \sqrt{2})\)

b

\((3,4,3-2 \sqrt{2})\)

c

\((1,-2,1+\sqrt{2})\)

d

\((1,2,1-\sqrt{2})\)

✓ Correct answer: b)

\((3,4,3-2 \sqrt{2})\)

Explanation

Given point P(1,0,7).

Given line:

\(\frac{\left(x−1\right)}{1}=\frac{y}{\left(−3\right)}=\frac{\left(z−8\right)}{1}\)

A point on line is A(1,0,8).

Direction ratios of line = (1,−3,1).

Find foot of perpendicular H from P to line.

Using reflection formula:

\({P}^{'}=2H−P\)

After applying angle conditions given in question, required point obtained is the option corresponding to (B).

Q16 FREE PREVIEW
PYQ

The shortest distance between the lines \(\frac{x-1}{2}=\frac{y-2}{3}=\frac{z-1}{4}\) and \(\frac{x+2}{7}=\frac{y-2}{8}=\frac{z+1}{2}\) is (22 Jan, Shift I, Memory Based)

a

\(\frac{88}{\sqrt{1277}}\)

b

\(\frac{78}{\sqrt{1277}}\)

c

\(\frac{66}{\sqrt{1277}}\)

d

\(\frac{55}{\sqrt{1277}}\)

✓ Correct answer: a)

\(\frac{88}{\sqrt{1277}}\)

Explanation

\(\begin{aligned}& A \equiv(1,2,1), C(-2,2,-1) \\& \text { where } \hat{\mathrm{n}}=\left|\begin{array}{lll}\hat{\mathrm{i}} & \hat{j} & \hat{k} \\2 & 3 & 4 \\7 & 8 & 2\end{array}\right|=-26 \hat{\mathrm{i}}+24 \hat{\mathrm{j}}-5 \hat{\mathrm{k}} \\& \\& =\left|\frac{(3 \hat{\mathrm{i}}+2 \hat{k}) \cdot(26 \hat{\mathrm{i}}-24 \hat{\mathrm{j}}+5 \hat{k})}{\sqrt{1277}}\right| \\& =\frac{78+10}{\sqrt{1277}}=\frac{88}{\sqrt{1277}}\end{aligned}\)

Q17
PYQ

Let a straight line L pass through the point \(\mathrm{P}(2,-1,3)\) and be perpendicular to the lines \(\frac{x-1}{2}=\frac{y+1}{1}=\frac{z-3}{-2}\)and \(\frac{x-3}{1}=\frac{y-2}{3}=\frac{z+2}{4}\). If the line \(L\) intersects the \(y z\)-plane at the point \(Q\), then the distance between the points \(P\)and \(Q\) is :

a

\(\sqrt{10}\)

b

2

c

3

d

\(2 \sqrt{3}\)

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Q18
PYQ

The shortest distance between the lines \(\frac{x-1}{2}=\frac{y-2}{3}=\frac{z-1}{4}\) and \(\frac{x+2}{7}=\frac{y-2}{8}=\frac{z+1}{2}\) is (22 Jan, Shift I, Memory Based)

a

\(\frac{88}{\sqrt{1277}}\)

b

\(\frac{78}{\sqrt{1277}}\)

c

\(\frac{66}{\sqrt{1277}}\)

d

\(\frac{55}{\sqrt{1277}}\)

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Q19
PYQ

\(\text { Perpendicular distance from the point } P(-2,0,2) \text { to the line } \frac{x+1}{2}=\frac{y-1}{-1}=\frac{z+3}{2}\) (22 Jan, Shift II, Memory Based)

a

\(5 \sqrt{5}\)

b

\(2 \sqrt{5}\)

c

\(3 \sqrt{2}\)

d

\(7 \sqrt{5}\)

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Q20
PYQ

If the square of the shortest distance between the lines \(\frac{x-2}{1}=\frac{y-1}{2}=\frac{z+3}{-3}\) and \(\frac{x+1}{2}=\frac{y+3}{4}=\frac{z+5}{-5}\) is \(\frac{m}{n}\), where \(m, n\) are coprime numbers, then \(m+n\) is equal to:

[JEE Main 2025, 23 Jan (Shift 2)]

a

6

b

9

c

21

d

14

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Q21
PYQ

Let the vertices Q and R of the triangle PQR lie on the line \(\frac{\mathrm{x}+3}{5}=\frac{\mathrm{y}-1}{2}=\frac{\mathrm{z}+4}{3},\mathrm{QR}=5\) and the coordinates of the point P be \((0,2,3)\). If the area of the triangle PQR is\(\frac{m}{n}\) then:

[JEE Main 2025, 2 Apr (Shift 1)]

a

\(\mathrm{m}-5\sqrt{21}\mathrm{n}=0\)

b

\(2\mathrm{m}-5\sqrt{21}\mathrm{n}=0\)

c

\(5\mathrm{m}-2\sqrt{21}\mathrm{n}=0\)

d

\(5\mathrm{m}-21\sqrt{2}\mathrm{n}=0\)

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Q22
PYQ

Let \(\text{P}\left(\alpha ,\beta ,\gamma \right)\) be the point on the line \(\frac{x−1}{2}=\frac{y+1}{−3}=z\) at a distance \(4\sqrt{14}\) from the point \((1, –1, 0)\) and nearer to the origin. Then the shortest distance, between the lines \(\frac{x−\alpha }{1}=\frac{y−\beta }{2}=\frac{z−\gamma }{3}\) and \(\frac{x+5}{2}=\frac{y−10}{1}=\frac{z−3}{1}\), is equal to

[JEE Main 2026, 22 Jan (Shift 1)]

a

\(4\sqrt{\frac{5}{7}}\)

b

\(2\sqrt{\frac{7}{4}}\)

c

\(7\sqrt{\frac{5}{4}}\)

d

\(4\sqrt{\frac{7}{5}}\)

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Q23
PYQ

Let the values of \(\lambda\) for which the shortest distance between the lines \(\frac{x-1}{2}=\frac{y-2}{3}=\frac{z-3}{4}\) and \(\frac{x-\lambda }{3}=\frac{y-4}{4}=\frac{z-5}{5}\) is \(\frac{1}{\sqrt{6}}\) be \({\lambda }_{1}\) and \({\lambda }_{2}\). Then the radius of the circle passing through the points \((0,0),\left({\lambda }_{1},{\lambda }_{2}\right)\) and \(\left({\lambda }_{2},{\lambda }_{1}\right)\) is

a

\(\frac{5\sqrt{2}}{3}\)

b

\(4\)

c

\(\frac{\sqrt{2}}{3}\)

d

\(3\)

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Q24
PYQ

Let \({\mathrm{L}}_{1}:\frac{\mathrm{x}-1}{1}=\frac{\mathrm{y}-2}{-1}=\frac{\mathrm{z}-1}{2}\) and \({L}_{2}:\frac{\mathrm{x}+1}{-1}=\frac{\mathrm{y}-2}{2}=\frac{\mathrm{z}}{1}\)be two lines. Let \(L_3\) be a line passing through the point \((\alpha ,\beta ,\gamma )\) and be perpendicular to both \(L_1\) and \(L_2\). If \(L_3\) intersects \({L}_1\), then \(|5\alpha -11\beta -8\gamma |\) equals :

[JEE Main 2025, 29 Jan (Shift 1)]

a

18

b

16

c

25

d

20

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Q25
PYQ

Let the direction cosines of two lines satisfy the equations: \(4l+m-n=0\) and \(2mn+10nl+3lm=0\). Then the cosine of the acute angle between these lines is:

a

\(\frac{20}{3\sqrt{38}}\)

b

\(\frac{10}{3\sqrt{38}}\)

c

\(\frac{10}{\sqrt{38}}\)

d

\(\frac{10}{7\sqrt{38}}\)

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Q26
PYQ

Let the foot of perpendicular from the point \((\lambda ,2,3)\) on the line \(\frac{x-4}{1}=\frac{y-9}{2}=\frac{z-5}{1}\) be the point \((1,\mu ,2)\). Then the distance between the lines \(\frac{x-1}{2}=\frac{y-2}{3}=\frac{z+4}{6}\) and \(\frac{x-\lambda }{2}=\frac{y-\mu }{3}=\frac{z+5}{6}\) is equal to:

[JEE Main 2026, 8 Apr (Shift 2)]

a

\(\frac{12}{7}\)

b

\(\frac{\sqrt{145}}{7}\)

c

\(\frac{\sqrt{146}}{7}\)

d

\(\frac{\sqrt{143}}{7}\)

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Q27
PYQ

Let a line \(L\) be perpendicular to both the line \({L}_{1}:\frac{x+1}{3}=\frac{y+3}{5}=\frac{z+5}{7}\) and \({L}_{2}:\frac{x-2}{1}=\frac{y-4}{4}=\frac{z-6}{7}\). If \(\theta\) is the acute angle between the lines \(L\) and \({L}_{3}:\frac{x-\frac{8}{7}}{2}=\frac{y-\frac{4}{7}}{1}=\frac{z}{2}\), then \(\tan \theta\) is equal to:

[JEE Main 2026, 6 Apr (Shift 1)]

a

\(\frac{3}{2}\sqrt{2}\)

b

\(\frac{5}{2}\sqrt{2}\)

c

\(\frac{5}{3}\sqrt{2}\)

d

\(\frac{4}{3}\sqrt{2}\)

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Q28
PYQ

The sum of all values of \(\alpha\), for which the shortest distance between the lines \(\frac{x+1}{\alpha }=\frac{y−2}{−1}=\frac{z−4}{−\alpha }\) and \(\frac{x}{\alpha }=\frac{y−1}{2}=\frac{z−1}{2\alpha }\) is \(\sqrt{2}\), is

[JEE Main 2026, 24 Jan (Shift 2)]

a

\(8\)

b

\(6\)

c

\(–8\)

d

\(–6\)

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Q29
PYQ

The distance of the line \(\frac{x-2}{2}=\frac{y-6}{3}=\frac{z-3}{4}\) from the point \((1,4,0)\) along the line \(\frac{x}{1}=\frac{y-2}{2}=\frac{z+3}{3}\) is :

[JEE Main 2025, 23 Jan (Shift 2)]

a

\(\sqrt{17}\)

b

\(\sqrt{14}\)

c

\(\sqrt{13}\)

d

\(\sqrt{15}\)

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Q30
PYQ

If the square of the shortest distance between the lines \(\frac{x-2}{1}=\frac{y-1}{2}=\frac{z+3}{-3}\) and \(\frac{x+1}{2}=\frac{y+3}{4}=\frac{z+5}{-5}\) is \(\frac{m}{n}\), where \(m, n\) are coprime numbers then \(\mathrm{m}+\mathrm{n}\) is equal to?

a

6

b

9

c

14

d

21

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Q31
PYQ

Let a triangle \(PQR\) be such that \(P\) and \(Q\) lie on the line \(\frac{x+3}{8}=\frac{y-4}{2}=\frac{z+1}{2}\) and are at a distance of \(6\) units from \(\mathrm{R}(1,2,3)\). If \((\alpha, \beta, \gamma)\) is the centroid of \(\triangle \mathrm{PQR}\), then \(\alpha+\beta+\gamma\) is equal to:

[JEE Main 2026, 5 Apr (Shift 2)]

a

\(4\)

b

\(5\)

c

\(6\)

d

\(8\)

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Q32
PYQ

The line \({\mathrm{L}}_{1}\) is parallel to the vector \(\vec{\mathrm{a}}=-3\hat{\mathrm{i}}+2\hat{\mathrm{j}}+4\hat{\mathrm{k}}\) and passes through the point \((7,6,2)\) and the line\({L}_{2}\) is parallel to the vector \(\vec{\mathrm{b}}=2\hat{\mathrm{i}}+\hat{\mathrm{j}}+3\hat{\mathrm{k}}\) and passes through the point \((5,3,4)\). The shortest distance between the lines \({L}_{1}\) and \({\mathrm{L}}_{2}\) is :

[JEE Main 2025, 2 Apr (Shift 2)]

a

\(\frac{23}{\sqrt{38}}\)

b

\(\frac{21}{\sqrt{57}}\)

c

\(\frac{23}{\sqrt{57}}\)

d

\(\frac{21}{\sqrt{38}}\)

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Q33
PYQ

Let \(L\), be the line \(\frac{x+1}{2}=\frac{y+1}{3}=\frac{z+3}{6}\) and let \(S\) be the set of all points \((a, b, c)\) on \(L\), whose distance from the line \(\frac{x+1}{2}=\frac{y+1}{3}=\frac{z−9}{0}\) along the line \(L\) is \(7\). Then \(\sum _{(a,\text{  }b,\text{  }c)\in S}(a+b+c)\) is equal

[JEE Main 2026, 22 Jan (Shift 2)]

a

40

b

34

c

28

d

6

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Q34
PYQ

The square of the distance of the point \((-2,-8,6)\) from the line \(\frac{x-1}{1}=\frac{y-1}{2}=\frac{z}{-1}\) along the line \(\frac{x+5}{1}=\frac{y+5}{-1}=\frac{z}{2}\)is equal to:

[JEE Main 2026, 4 Apr (Shift 1)]

a

\(3\)

b

\(6\)

c

\(8\)

d

\(12\)

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Q35
PYQ

Let the lines \({L}_{1}:\vec{r}=\hat{i}+2\hat{j}+3\hat{k}\)

\(+\text{ }\lambda \left(2\hat{i}+3\hat{j}+4\hat{k}\right),\lambda \in R\) and

\({L}_{2}:\vec{r}\text{ }=\text{ }\left(4\hat{i}\text{ }+\text{ }\hat{j}\right)\text{ }+\text{ }\mu \left(5\hat{i}\text{ }+\text{ }2\hat{j}+\hat{k}\right),\)

\(\mu \text{ }\in \text{ }R,\) intersect at the point R.

Let P and Q be the points lying on lines

\({L}_{1}\) and \({L}_{2}\), respectively, such that

\(\left|\vec{PR}\right|=\sqrt{29}\) and \(\left|\vec{PQ}\right|=\sqrt{\frac{47}{3}}.\)

If the point P lies in the first octant, then \(27{\left(QR\right)}^{2}\) is equal to

a

\(360\)

b

\(348\)

c

\(340\)

d

\(320\)

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Q36
PYQ

Let a line pass through two distinct points \(P(-2,-1,3)\) and Q, and be parallel to the vector \(3\hat{i}+2\hat{j}+2\hat{k}\). If the distance of the point Q from the point \(R(1,3,3)\) is 5 , then the square of the area of \(\triangle \mathrm{PQR}\) is equal to:

[JEE Main 2025, 22 Jan (Shift 2)]

a

136

b

140

c

144

d

148

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Q37
PYQ

Let the line passing through the point \((–1, 2, 1)\) and parallel to the line \(\frac{x-1}{2}=\frac{y+1}{3}=\frac{z}{4}\)intersect the line \(\frac{x+2}{3}=\frac{y-3}{2}=\frac{z-4}{1}\)at the point P. Then the distance of P from the point \(Q(4, – 5, 1)\) is :

[JEE Main 2025, 24 Jan (Shift 1)]

a

5

b

10

c

\(5\sqrt{6}\)

d

\(5\sqrt{5}\)

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Q38
PYQ

Let the values of \(p\), for which the shortest distance between the lines \(\frac{x+1}{3}=\frac{y}{4}=\frac{z}{5}\) and \(\vec{\mathrm{r}}=(\mathrm{p}\hat{\mathrm{i}}+2\hat{\mathrm{j}}+\hat{\mathrm{k}})+\lambda (2\hat{\mathrm{i}}+3\hat{\mathrm{j}}+4\hat{\mathrm{k}})\) is \(\frac{1}{\sqrt{6}}\), be \(\mathrm{a},\mathrm{b}\), \((\mathrm{a}<\mathrm{b})\). Then the length of the latus rectum of the ellipse \(\frac{{x}^{2}}{{a}^{2}}+\frac{{y}^{2}}{{b}^{2}}=1\) is :-

[JEE Main 2025, 4 Apr (Shift 1)]

a

\(9\)

b

\(\frac{3}{2}\)

c

\(\frac{2}{3}\)

d

\(18\)

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Q39
PYQ

Let the acute angle bisector of the two planes \(x-2 y-2 z+1=0\) and \(2 x-3 y-6 z+1=0\) be the plane \(P\). Then which of the following points lies on \(P\) ?

a

\(\left(3,1,-\frac{1}{2}\right)\)

b

\(\left(-2,0,-\frac{1}{2}\right)\)

c

\((0,2,-4)\)

d

\((4,0,-2)\)

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Q40
PYQ

\({\mathrm{L}}_{1}=\frac{x-1}{1}=\frac{y-2}{-1}=\frac{z-1}{2},{L}_{2}:\frac{x+1}{-1}=\frac{y-2}{2}=\frac{z}{1}\)

Let the line \({\mathrm{L}}_{3}\) passes through the point \((\alpha ,\beta ,\gamma )\) perpendicular to \({L}_{1}\&{L}_{2}\) and \({L}_{3}\) intersect line \({L}_{1}\) then \(|5\alpha -11\beta -8\gamma |\).

a

25

b

18

c

16

d

20

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Q41
PYQ

\({\mathrm{L}}_{1}=\frac{x-1}{1}=\frac{y-2}{-1}=\frac{z-1}{2},{L}_{2}:\frac{x+1}{-1}=\frac{y-2}{2}=\frac{z}{1}\)

Let the line \({\mathrm{L}}_{3}\) passes through the point \((\alpha ,\beta ,\gamma )\) perpendicular to \({L}_{1}\&{L}_{2}\) and \({L}_{3}\) intersect line \({L}_{1}\) then \(|5\alpha -11\beta -8\gamma |\).

a

25

b

18

c

16

d

20

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Q42
PYQ

Let \(\text{P}\left(\alpha ,\beta ,\gamma \right)\) be the point on the line \(\frac{x−1}{2}=\frac{y+1}{−3}=z\) at a distance \(4\sqrt{14}\) from the point \((1, –1, 0)\) and nearer to the origin. Then the shortest distance, between the lines \(\frac{x−\alpha }{1}=\frac{y−\beta }{2}=\frac{z−\gamma }{3}\) and \(\frac{x+5}{2}=\frac{y−10}{1}=\frac{z−3}{1}\), is equal to

[JEE Main 2026, 22 Jan (Shift 1)]

a

\(4\sqrt{\frac{5}{7}}\)

b

\(2\sqrt{\frac{7}{4}}\)

c

\(7\sqrt{\frac{5}{4}}\)

d

\(4\sqrt{\frac{7}{5}}\)

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Q43
PYQ

If the square of the shortest distance between the lines \(\frac{x-2}{1}=\frac{y-1}{2}=\frac{z+3}{-3}\) and \(\frac{x+1}{2}=\frac{y+3}{4}=\frac{z+5}{-5}\) is \(\frac{m}{n}\), where \(m, n\) are coprime numbers, then \(m+n\) is equal to:

a

6

b

9

c

21

d

14

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Q44
PYQ

If the point of intersection of the lines \(\frac{x+1}{3}=\frac{y+a}{5}=\frac{z+b+1}{7}\) and \(\frac{x-2}{1}=\frac{y-b}{4}=\frac{z-2a}{7}\) lies on \(xy-\)plane, then the value of \(a+b\) is:

[JEE Main 2026, 2 Apr (Shift 1)]

a

\(2\)

b

\(5\)

c

\(7\)

d

\(9\)

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Q45
PYQ

If the image of the point \(\mathrm{P}(1,0,3)\) in the line joining the points \(\mathrm{A}(4,7,1)\) and \(\mathrm{B}(3,5,3)\) is \(Q(\alpha ,\beta ,\gamma )\), then \(\alpha +\beta +\gamma\) is equal to

[JEE Main 2025, 2 Apr (Shift 2)]

a

\(\frac{47}{3}\)

b

\(\frac{46}{3}\)

c

\(18\)

d

\(13\)

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Q46
PYQ

\(A\) and \(C\) are two points on the line \(\frac{x-6}{3}=\frac{y-7}{2}=\frac{z-7}{-2}\) such that \(A C=6 . \quad B\) is \((1,1,-2)\). Find area of \(\triangle A B C\). (24 Jan, Shift I, Memory Based)

a

33

b

32

c

35

d

None of these

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Q47
PYQ

The perpendicular distance of point \(P(3,2,5)\) from the line \(\vec{r}=2 \hat{\imath}-\hat{\jmath}+\hat{k}+\lambda(4 \hat{\imath}-\hat{\jmath}+5 \hat{k})\) is (22 Jan, Shift II, Memory Based)

a

\(\sqrt{\frac{31}{2}}\)

b

\(\sqrt{\frac{19}{42}}\)

c

\(\sqrt{\frac{42}{19}}\)

d

\(\sqrt{\frac{21}{19}}\)

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Q48
PYQ

\(\text { Perpendicular distance from the point } P(-2,0,2) \text { to the line } \frac{x+1}{2}=\frac{y-1}{-1}=\frac{z+3}{2}\) (22 Jan, Shift II, Memory Based)

a

\(5 \sqrt{5}\)

b

\(2 \sqrt{5}\)

c

\(3 \sqrt{2}\)

d

\(7 \sqrt{5}\)

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Q49
PYQ

The sum of all values of \(\alpha\), for which the shortest distance between the lines \(\frac{x+1}{\alpha }=\frac{y−2}{−1}=\frac{z−4}{−\alpha }\) and \(\frac{x}{\alpha }=\frac{y−1}{2}=\frac{z−1}{2\alpha }\) is \(\sqrt{2}\), is

[JEE Main 2026, 24 Jan (Shift 2)]

a

\(8\)

b

\(6\)

c

\(–8\)

d

\(–6\)

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Q50
PYQ

The perpendicular distance of point \(P(3,2,5)\) from the line \(\vec{r}=2 \hat{\imath}-\hat{\jmath}+\hat{k}+\lambda(4 \hat{\imath}-\hat{\jmath}+5 \hat{k})\) is (22 Jan, Shift II, Memory Based)

a

\(\sqrt{\frac{31}{2}}\)

b

\(\sqrt{\frac{19}{42}}\)

c

\(\sqrt{\frac{42}{19}}\)

d

\(\sqrt{\frac{21}{19}}\)

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Q51
PYQ

Let the line L be \(\frac{x-1}{1}=\frac{y-4}{3}=\frac{z-7}{5}\) and foot of perpendicular from (1,-2,-1) to L is \((\alpha ,\beta ,\gamma )\), then \(\alpha +\beta +\gamma\) is :

a

\(\frac{-69}{35}\)

b

\(\frac{102}{35}\)

c

\(\frac{69}{35}\)

d

\(\frac{-102}{35}\)

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Q52
PYQ

\({\mathrm{L}}_{1}=\frac{x-1}{1}=\frac{y-2}{-1}=\frac{z-1}{2},{L}_{2}:\frac{x+1}{-1}=\frac{y-2}{2}=\frac{z}{1}\)

Let the line \({\mathrm{L}}_{3}\) passes through the point \((\alpha ,\beta ,\gamma )\) perpendicular to \({L}_{1}\&{L}_{2}\) and \({L}_{3}\) intersect line \({L}_{1}\) then \(|5\alpha -11\beta -8\gamma |\).

a

25

b

18

c

16

d

20

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Q53
PYQ

Let a line \(L\) passing through the point \((1,1,1)\) be perpendicular to both the vectors \(2\hat{i}+2\hat{j}+\hat{k}\) and \(\hat{i}+2\hat{j}+2\hat{k}\). If \(P(a,b,c)\) is the foot of perpendicular from the origin on the line \(L\), then the value of \(34(a+b+c)\) is:

[JEE Main 2026, 2 Apr (Shift 1)]

a

\(50\)

b

\(80\)

c

\(100\)

d

\(120\)

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Q54
PYQ

The shortest distance between the lines \(\vec{r}=\left(\frac{1}{3}\hat{i}+2\hat{j}+\frac{8}{3}\hat{k}\right)+\lambda (2\hat{i}-5\hat{j}+6\hat{k})\) and \(\vec{r}=\left(-\frac{2}{3}\hat{i}-\frac{1}{3}\hat{k}\right)+\mu (\hat{j}-\hat{k}),\lambda ,\mu \in R\), is:

[JEE Main 2026, 4 Apr (Shift 2)]

a

\(\sqrt{5}\)

b

\(3\)

c

\(2\sqrt{3}\)

d

\(\sqrt{15}\)

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Q55
PYQ

\(A\) and \(C\) are two points on the line \(\frac{x-6}{3}=\frac{y-7}{2}=\frac{z-7}{-2}\) such that \(A C=6 . \quad B\) is \((1,1,-2)\). Find area of \(\triangle A B C\). (24 Jan, Shift I, Memory Based)

a

33

b

32

c

35

d

None of these

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Q56
PYQ

The length of the perpendicular drawn from the point \(\ (3,-1,11) \) to the line \(\ \frac{x}{2}=\frac{y-2}{3}=\frac{z-3}{4} \) is :

a

\(\ \sqrt{29} \)

b

\(\ \sqrt{33} \)

c

\(\ \sqrt{53} \)

d

\(\ \sqrt{66} \)

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Q57
PYQ

The distance of the point \(P(4,6,-2)\) from the line passing through the point \((-3,2,3)\) and parallel to a line with direction ratios \(3,3,-1\) is equal to:

[JEE Main 2023, 25 Jan (Shift 1)]

a

3

b

\(\sqrt{6}\)

c

\(2 \sqrt{3}\)

d

\(\sqrt{14}\)

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Q58
PYQ

The distance of the point \((-1,9,-16)\) from the plane \(2 x+3 y\) \(-z=5\) measured parallel to the line \(\frac{x+4}{3}=\frac{2-y}{4}=\frac{z-3}{12}\)

[JEE Main 2023, 24 Jan (Shift 1)]

a

\(13 \sqrt{2}\)

b

\(31\)

c

\(26\)

d

\(20 \sqrt{2}\)

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Q59
PYQ

Let the plane \(P\) pass through the intersection of the planes \(2 x+3 y-z=2\) and \(x+2 y+3 z=6\), and be perpendicular to the plane \(2 x+y-z+1=0\). If \(d\) is the distance of \(P\) from the point \((-7,1,1)\), then \(d^2\) is equal to

[JEE Main 2023, 1 Feb (Shift 2)]

a

\(\frac{250}{83}\)

b

\(\frac{15}{53}\)

c

\(\frac{25}{83}\)

d

\(\frac{250}{82}\)

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Q60
PYQ

Shortest distance between the lines \(\frac{x-1}{2}=\frac{y+8}{-7}=\frac{z-4}{5}\) and \(\frac{x-1}{2}=\frac{y-2}{1}=\frac{z-6}{-3}\) is

[JEE Main 2023, 29 Jan (Shift 2)]

a

\(2 \sqrt{3}\)

b

\(4 \sqrt{3}\)

c

\(3 \sqrt{3}\)

d

\(5 \sqrt{3}\)

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Q61
PYQ

If the equation of the plane containing the line \(x+2 y+\) \(3 z-4=0=2 x+y-z+5\) and perpendicular to the plane \(\vec{r}=(\hat{i}-\hat{j})+\lambda(\hat{i}+\hat{j}+\hat{k})+\mu(\hat{i}-2 \hat{j}+3 \hat{k})\) is \(a x+b y+c z\) \(=4\), then \((a-b+c)\) is equal to

[JEE Main 2023, 8 Apr (Shift 1)]

a

18

b

22

c

20

d

24

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Q62
PYQ

The equation of the plane passing through the line of intersection of the planes \(\vec{r} \cdot(\hat{i}+\hat{j}+\hat{k})=1\) and \(\vec{r} \cdot(2 \hat{i}+3 \hat{j}-\hat{k})+4=0\) and parallel to the \(x\)-axis is

[JEE Main 2021, 27 Aug (Shift 2)]

a

\(\vec{r} \cdot(\hat{j}-3 \hat{k})-6=0\)

b

\(\vec{r} \cdot(\hat{i}+3 \hat{k})+6=0\)

c

\(\vec{r} \cdot(\hat{j}-3 \hat{k})+6=0\)

d

\(\vec{r} \cdot(\hat{i}-3 \hat{k})+6=0\)

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Q63
PYQ

Let the plane containing the line of intersection of the planes \(P_1: x+(\lambda+4) y+z=1\) and
\(P_2: 2 x+y+z=2\) pass through the points \((0,1,0)\) and \((1,0,1)\). Then the distance of the point \((2 \lambda, \lambda,-\lambda)\) from the plane \(P_2\) is

a

\(5 \sqrt{6}\)

b

\(4 \sqrt{6}\)

c

\(2 \sqrt{6}\)

d

\(3 \sqrt{6}\)

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Q64
PYQ

The equation of the line through the point \((0,1,2)\) and perpendicular to the line \(\frac{x-1}{2}=\frac{y+1}{3}=\frac{z-1}{-2}\) is:

[JEE Main 2021, 25 Feb (Shift 1)]

a

\(\frac{x}{3}=\frac{y-1}{4}=\frac{z-2}{3}\)

b

\(\frac{x}{-3}=\frac{y-1}{4}=\frac{z-2}{3}\)

c

\(\frac{x}{3}=\frac{y-1}{4}=\frac{z-2}{-3}\)

d

\(\frac{x}{3}=\frac{y-1}{-4}=\frac{z-2}{3}\)

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Q65
PYQ

If equation of the plane that contains the point \((-2,3,5)\) and is perpendicular to each of the planes \(2 x+4 y+5 z\) \(=8\) and \(3 x-2 y+3 z=5\) is \(\alpha x+\beta y+\gamma z+97=0\) then \(\alpha+\beta+\gamma=\)

[JEE Main 2023, 11 Apr (Shift 1)]

a

18

b

17

c

16

d

15

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Q66
PYQ

If \((x, y, z)\) be an arbitrary point lying on a plane \(P\) which passes through the points \((42,0,0),(0,42,0)\) and \((0,0\), 42), then the value of the expression
\[\begin{aligned}& 3+\frac{x-11}{(y-19)^2(z-12)^2}+\frac{y-9}{(x-11)^2(z-12)^2} \\&+\frac{z-12}{(x-11)^2(y-19)^2}-\frac{x+y+z}{14(x-11)(y-19)(z-12)}\end{aligned}\] is equal to

[JEE Main 2021, 16 Mar (Shift 2)]

a

3

b

0

c

-45

d

39

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Q67
PYQ

The shortest distance between the lines x + 1 = 2y = –12z and x = y + 2 = 6z – 6 is

a

2

b

3

c

\(\frac{5}{2}\)

d

\(\frac{3}{2}\)

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Q68
PYQ

The equation of the plane passing through the point (1, \(2,-3)\) and perpendicular to the planes \(3 x+y-2 z=5\) and \(2 x-5 y-z=7\), is:

[JEE Main 2021, 24 Feb (Shift 1)]

a

\(6 x-5 y+2 z+10=0\)

b

\(3 x-10 y-2 z+11=0\)

c

\(11 x+y+17 z+38=0\)

d

\(6 x-5 y-2 z-2=0\)

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Q69
PYQ

The line, that is coplanar to the line \(\frac{x+3}{-3}=\frac{y-1}{1}=\frac{z-5}{5}\), is

[JEE Main 2023, 13 Apr (Shift 2)]

a

\(\frac{x+1}{1}=\frac{y-2}{2}=\frac{z-5}{5}\)

b

\(\frac{x+1}{-1}=\frac{y-2}{2}=\frac{z-5}{5}\)

c

\(\frac{x+1}{-1}=\frac{y-2}{2}=\frac{z-5}{4}\)

d

\(\frac{x-1}{-1}=\frac{y-2}{2}=\frac{z-5}{5}\)

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Q70
PYQ

Let \(P\) be the plane, passing through the point \((1,-1,-5)\) and perpendicular to the line joining the points \((4,1,-3)\) and \((2,4,3)\). Then the distance of \(P\) from the point \((3,-2,2)\) is

[JEE Main 2023, 31 Jan (Shift 2)]

a

6

b

4

c

5

d

7

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Q71
PYQ

Let \(P\) be the plane passing through the points \((5,3,0)\), \((13,3,-2)\) and \((1,6,2)\). For \(\alpha \in N\), if the distances of the points \(A(3,4, \alpha)\) and \(B(2, \alpha, a)\) from the plane \(P\) are 2 and 3 respectively, then the positive value of \(a\) is

[JEE Main 2023, 11 Apr (Shift 2)]

a

6

b

4

c

3

d

5

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Q72
PYQ

Let two vertices of triangle \(A B C\) be \((2,4,6)\) and \((0,-2\), \(-5)\), and its centroid be \((2,1,-1)\). If the image of third vertex in the plane \(x+2 y+4 z=11\) is \((\alpha, \beta, \gamma)\), then \(\alpha \beta+\) \(\beta \gamma+\gamma \alpha\) is equal to

[JEE Main 2023, 10 Apr (Shift 1)]

a

72

b

74

c

76

d

70

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Q73
PYQ

If the lines \(\frac{x-1}{1}=\frac{y-2}{2}=\frac{z+3}{1}\) and \(\frac{x-a}{2}=\frac{y+2}{3}=\frac{z-3}{1}\) intersects at the point \(P\), then the distance of the point \(P\) from the plane \(z=a\) is:

[JEE Main 2023, 29 Jan (Shift 2)]

a

16

b

28

c

10

d

22

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Q74
PYQ

Consider the line \(L\) given by the equation
\(\frac{x-3}{2}=\frac{y-1}{1}=\frac{z-2}{1}\). Let \(Q\) be the mirror image of the point \((2,3,-1)\) with respect to \(L\). Let a plane \(P\) be such that it passes through \(Q\), and the line \(L\) is perpendicular to \(P\). Then which of the following points is on the plane \(P\) ?

[JEE Main 2021, 20 Jul (Shift 2)]

a

\((1,2,2)\)

b

\((-1,1,2)\)

c

\((1,1,1)\)

d

\((1,1,2)\)

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Q75
PYQ

The shortest distance between the lines \(\frac{x-5}{1}=\frac{y-2}{2}=\frac{z-4}{-3}\) and \(\frac{x+3}{1}=\frac{y+5}{4}=\frac{z-1}{-5}\) is

[JEE Main 2023, 1 Feb (Shift 1)]

a

\(7 \sqrt{3}\)

b

\(5 \sqrt{3}\)

c

\(6 \sqrt{3}\)

d

\(4 \sqrt{3}\)

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Q76
PYQ

If the equation of the plane passing through the line of intersection of the planes \(2 x-y+z=3,\) \(4 x-3 y+5 z+9=0\) and parallel to the line \(\frac{x+1}{-2}=\frac{y+3}{4}=\frac{z-2}{5}\) is \(a x+b y+\) \(c z+6=0\). then \(a+b+c\) is equal to

[JEE Main 2023, 6 Apr (Shift 1)]

a

14

b

12

c

13

d

15

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Q77
PYQ

Let \(P\) be the plane, passing through the point \((1,-1,-5)\) and perpendicular to the line joining the points \((4,1,-3)\) and \((2,4,3)\). Then the distance of \(P\) from the point \((3,-2,2)\) is

a

6

b

4

c

5

d

7

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Q78
PYQ

Let the plane \(P: 8 x+\alpha_1 y+\alpha_2 z+12=0\) be parallel to the line \(L: \frac{x+2}{2}=\frac{y-3}{3}=\frac{z+4}{5}\). If the intercept of \(P\) on the \(y\)-axis is 1 , then the distance between \(P\) and \(L\) is:

[JEE Main 2023, 31 Jan (Shift 2)]

a

\(\sqrt{14}\)

b

\(\frac{6}{\sqrt{14}}\)

c

\(\sqrt{\frac{2}{7}}\)

d

\(\sqrt{\frac{7}{2}}\)

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Q79
PYQ

A line makes angles of \(\ 45^{\circ} \) and \(\ 60^{\circ} \) with the positive axes of \(\ X \) and \(\ Y \) respectively. The angle made by the same line with the positive axis of \(\ Z \) , is.

a

\(\ 30^{\circ} \) or \(\ 60^{\circ} \)

b

\(\ 60^{\circ} \) or \(\ 90^{\circ} \)

c

\(\ 90^{\circ} \) or \(\ 120^{\circ} \)

d

\(\ 60^{\circ} \) or \(\ 120^{\circ} \)

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Q80
PYQ

Let the lines \(l_1: \frac{x+5}{3}=\frac{y+4}{1}=\frac{z-\alpha}{-2}\) and \(l_2: 3 x+2 y+z-2=0=x-3 y+2 z-13\) be coplanar. If the point \(P(a, b, c)\) on \(l_1\) is nearest to the point \(Q(-4,-3,2)\), then \(|a|+|b|+|c|\) is equal to

[JEE Main 2023, 12 Apr (Shift 1)]

a

\(12\)

b

\(14\)

c

\(10\)

d

\(8\)

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Q81
PYQ

Let the foot of perpendicular from a point \(P(1,2\), \(-1)\) to the straight line \(L: \frac{x}{1}=\frac{y}{0}=\frac{z}{-1}\) be \(N\). Let a line be drawn from \(P\) parallel to the plane \(x+y+\) \(2 z=0\) which meets \(L\) at point \(Q\). If \(\alpha\) is the acuteangle between the lines \(P N\) and \(P Q\), then \(\cos \alpha\) is equal to:

[JEE Main 2021, 25 Jul (Shift 1)]

a

\(\frac{1}{\sqrt{5}}\)

b

\(\frac{\sqrt{3}}{2}\)

c

\(\frac{1}{\sqrt{3}}\)

d

\(\frac{1}{2 \sqrt{3}}\)

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Q82
PYQ

A plane \(P\) contains the line of intersection of the plane \(\vec{r} \cdot(\hat{i}+\hat{j}+\hat{k})=6\) and \(\vec{r} \cdot(2 \hat{i}+3 \hat{j}+4 \hat{k})=-5\). If \(P\) passes through the point \((0,2,-2)\), then the square of distance of the point \((12,12,18)\) from the plane \(P\) is

[JEE Main 2023, 6 Apr (Shift 2)]

a

1240

b

620

c

310

d

155

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Q83
PYQ

The foot of perpendicular from the origin \(O\) to a plane \(P\) which meets the co-ordinate axes at the points \(A, B, C\) is \((2, a, 4), a \in N\). If the volume of the tetrahedron \(O A B C\) is \(144\) unit\(^3\), then which of the following points is NOT on \(P\) ?

[JEE Main 2023, 31 Jan (Shift 2)]

a

(2,2,4)

b

(0,4,4)

c

(3,0,4)

d

(0,6,3)

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Q84
PYQ

The foot of perpendicular of the point \((2,0,5)\) on the line \(\frac{x+1}{2}=\frac{y-1}{5}=\frac{z+1}{-1}\) is \((\alpha, \beta, \gamma)\). Then which of the following is NOT correct?

[JEE Main 2023, 25 Jan (Shift 2)]

a

\(\frac{\alpha \beta}{\gamma}=\frac{4}{15}\)

b

\(\frac{\alpha}{\beta}=-8\)

c

\(\frac{\beta}{\gamma}=-5\)

d

\(\frac{\gamma}{\alpha}=\frac{5}{8}\)

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Q85
PYQ

The shortest distance between the lines \(\frac{x−4}{4}=\frac{y+2}{5}=\frac{z+3}{3}\) and \(\frac{x−1}{3}=\frac{y−3}{4}=\frac{z−4}{2}\) is

[JEE Main 2023, 08 Apr (Shift 1)]

a

\(6\sqrt{3}\)

b

\(2\sqrt{6}\)

c

\(6\sqrt{2}\)

d

\(3\sqrt{6}\)

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Q86
PYQ

One vertex of a rectangular parallelopiped is at the origin \(O\) and the lengths of its edges along \(x, y\) and \(z\) axes are \(3 , 4\) and \(5\) units respectively. Let \(P\) be the vertex \((3,4,5)\).Then the shortest distance between the diagonal \(O P\) and an edge parallel to \(z\) axis, not passing through \(O\) or \(P\) is:

a

\(\frac{12}{\sqrt{5}}\)

b

\(\frac{12}{5 \sqrt{5}}\)

c

\(12 \sqrt{5}\)

d

\(\frac{12}{5}\)

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Q87
PYQ

The shortest distance between the lines \(\frac{x+2}{1}=\frac{y}{-2}=\frac{z-5}{2}\) and \(\frac{x-4}{1}=\frac{y-1}{2}=\frac{z+3}{0}\) is

a

6

b

9

c

7

d

8

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Q88
PYQ

For \(a, b \in Z\) and \(|a-b| \leq 10\), let the angle between the plane \(P: a x+y-z=b\) and the line \(l: x-1=a-y=z+1\) be \(\cos ^{-1}\left(\frac{1}{3}\right)\) If the distance of the point \((6,-6,4)\) from the plane \(P\) is \(3 \sqrt{6}\), then \(a^4+b^2\) is equal to

[JEE Main 2023, 08 Apr (Shift 2)]

a

25

b

85

c

48

d

32

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Q89
PYQ

The plane which bisects the line joining, the points \( (4,-2,3) \) and \( (2,4,-1) \) at right angles also passes through the point:


[JEE Main 2020, 3 Sep (Shift 2)]

a

\( (4,0,1) \)

b

\( (0,-1,1) \)

c

\( (0,1,-1) \)

d

\( (4,0,-1) \)

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Q90
PYQ

If the shortest distance between the straight lines \(3(x-1)=6(y-2)=2(z-1)\) and \(4(x-2)=2(y-\lambda)=(z-3), \lambda \in R\) is \(\frac{1}{\sqrt{38}}\), then the integral value of \(\lambda\) is equal to:

[JEE Main 2021, 22 Jul (Shift 2)]

a

3

b

2

c

-1

d

5

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Q91
PYQ

The foot of the perpendicular drawn from the point \((4,2,3)\) to the line joining the points \((1,-2,3)\) and \((1,1,0)\) lies on the plane:

[JEE Main 2020, 3 Sep (Shift 1)]

a

\(\ x-y-2 z=1 \)

b

\(\ 2 x+y-z=1\)

c

\(\ x-2 y+z=1\)

d

\(\ x+2 y-z=1\)

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Q92
PYQ

Consider the line \(L\) given by the equation
\(\frac{x-3}{2}=\frac{y-1}{1}=\frac{z-2}{1}\). Let \(Q\) be the mirror image of the point \((2,3,-1)\) with respect to \(L\). Let a plane \(P\) be such that it passes through \(Q\), and the line \(L\) is perpendicular to \(P\). Then which of the following points is one the plane \(P\) ?


[JEE Main 2021, 20 Jul (Shift 2)]

a

(1,2,2)

b

(-1,1,2)

c

(1,1,1)

d

(1,1,2)

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Q93
PYQ

Let the image of the point \(P(1,2,6)\) in the plane passing through the points \(A(1,2,0), B(1,4,1)\) and \(C(0,5,1)\) be \(Q(\alpha, \beta, \gamma)\). Then \(\left(\alpha^2+\beta^2+\gamma^2\right)\) is equal to:

[JEE Main 2023, 10 Apr (Shift 2)]

a

65

b

70

c

76

d

62

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Q94
PYQ

The distance of the point \((-1,2,-2)\) from the line of intersection of the planes \(2 x+3 y+2 z=0\) and \(x-2 y+z=0\)

[JEE Main 2021, 31 Aug (Shift 2)]

a

\(\frac{5}{2}\)

b

\(\frac{\sqrt{42}}{2}\)

c

\(\frac{1}{\sqrt{2}}\)

d

\(\frac{\sqrt{34}}{2}\)

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Q95
PYQ

For \(a, b \in Z\) and \(|a-b| \leq 10\), let the angle between the plane \(P: a x+y-z=b\) and the line \(l: x-1=a-y=z+1\) be \(\cos ^{-1}\left(\frac{1}{3}\right)\) If the distance of the point \((6,-6,4)\) from the plane \(P\) is \(3 \sqrt{6}\), then \(a^4+b^2\) is equal to

[JEE Main 2023, 8 Apr (Shift 2)]

a

25

b

85

c

48

d

32

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Q96
PYQ

If the mirror image of the point \((1,3,5)\) with respect to the plane \(4 x-5 y+2 z=8\) is \((\alpha, \beta, \gamma)\) then \(5(\alpha+\beta+\gamma)\) equals:

[JEE Main 2021, 26 Feb (Shift 2)]

a

41

b

39

c

47

d

43

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Q97
PYQ

The plane \(2 x-y+z=4\) intersects the line segment joining the points \(A(a,-2,4)\) and \(B(2, b,-3)\) at the point \(C\) in the ratio 2: 1 and the distance of the point \(C\) from the origin is \(\sqrt{5}\). If \(a b<0\) and \(P\) is the point \((a-b, b, 2 b-a)\) then \(C P^2\) is equal to:

[JEE Main 2023, 29 Jan (Shift 2)]

a

\(\frac{17}{3}\)

b

\(\frac{16}{3}\)

c

\(\frac{73}{3}\)

d

\(\frac{97}{3}\)

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Q98
PYQ

Let the plane containing the line of intersection of the planes \(P_1: x+(\lambda+4) y+z=1\) and \(P_2: 2 x+y+z=2\) pass through the points \((0,1,0)\) and \((1,0,1)\). Then the distance of the point \((2 \lambda, \lambda,-\lambda)\) from the plane \(P_2\) is

[JEE Main 2023, 24 Jan (Shift 2)]

a

\(5 \sqrt{6}\)

b

\(4 \sqrt{6}\)

c

\(2 \sqrt{6}\)

d

\(3 \sqrt{6}\)

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Q99
PYQ

Let the equation of the plane, that passes through the point \(\left( 1,4, - 3 \right)\)and and contains the line of intersection of the planes \(3x - 2y + 4z - 7 = 0\) and \(x + 5y - 2z + 9 = 0\), be \(\alpha x\ + \beta y + \gamma z + 3 = 0\) then \(\alpha + \beta + \gamma\) is equal to?

[JEE Main 2021, 31 Aug (Shift 1)]

a

-15

b

15

c

-23

d

23

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Q100
PYQ

The lines \(\vec{r}=(\hat{i}-\hat{j})+l(2 \hat{i}+\hat{k})\) and \(\vec{r}=(2 \hat{i}-\hat{j})+m(\hat{i}+\hat{j}-\hat{k})\)


[JEE Main 2020, 3 Sep (Shift 1)]

a

Do not intersect for any values of \(l\) and \(m\)

b

Intersect for all values of \(l\) and \(m\)

c

Intersect when \(l=2\) and \(m=\frac{1}{2}\)

d

Intersect when \(l=1\) and \(m=2\)

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Q101
PYQ

Let \(L\) be the line of intersection of planes \(\vec{r} \cdot(\hat{i}-\hat{j}+2 \hat{k})=2\) and \(\vec{r} \cdot(2 \hat{i}+\hat{j}-\hat{k})=2\). If \(P(\alpha, \beta, \lambda)\) is the foot of perpendicular on \(L\) from the point \((1,2,0)\), then the value of \(35(\alpha+\beta+\lambda)\) is equal to:

[JEE Main 2021, 22 Jul (Shift 2)]

a

101

b

143

c

134

d

119

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Q102
PYQ

A line makes angles of 45° and 60° with the positive axes of \(X\) and \(Y\) respectively. The angle made by the same line with the positive axis of \(Z,\) is

a

30° or 60°

b

60° or 90°

c

90° or 120°

d

60° or 120°

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Q103
PYQ

Let \(\alpha\) be the angle between the lines whose direction cosines satisfy the equations \(l+m-n=0\) and \(l^2+m^2-n^2\) \(=0\). Then the value of \(\sin ^4 \alpha+\cos ^4 \alpha\) is:

[JEE Main 2021, 25 Feb (Shift 1)]

a

\(\frac{1}{2}\)

b

\(\frac{5}{8}\)

c

\(\frac{3}{8}\)

d

\(\frac{3}{4}\)

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Q104
PYQ

Let the plane \(P: 4 x-y+z=10\) be rotated by an angle \(\pi / 2\) about its line of intersection with the plane \(x+y-z=4\). If \(\alpha\) is the distance of the point \((2,3,-4)\) from the new position of the plane \(P\), then \(35 \alpha\) is

[JEE Main 2023, 12 Apr (Shift 1)]

a

90

b

85

c

105

d

126

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Q105
PYQ

Equation of a plane at a distance \(\sqrt{\frac{2}{21}}\) from the origin, which contains the line of intersection of the planes \(x-y-z-1\) \(=0\) and \(2 x+y-3 z+4=0\), is:


[JEE Main 2021, 27 Aug (Shift 1)]

a

\(3 x-4 z+3=0\)

b

\(\vec{r} \cdot(3 \hat{i}+7 \hat{j}+3 \hat{k})=7\)

c

\(4 x-y-5 z+2=0\)

d

\(-x+2 y+2 z-3=0\)

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Q106
PYQ

If for \(a>0\), the feet of perpendiculars from the points \(A\) \((a,-2 a, 3)\) and \(B(0,4,5)\) on the plane \(lx+m y+n z=0\) are points \(C(0,-a,-1)\) and \(D\) respectively, then the length of line segment \(C D\) is equal to:

[JEE Main 2021, 16 Mar (Shift 1)]

a

\(\sqrt{41}\)

b

\(\sqrt{31}\)

c

\(\sqrt{66}\)

d

\(\sqrt{55}\)

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Q107
PYQ

If \((x, y, z)\) be an arbitrary point lying on a plane \(P\) which passes through the points \((42,0,0),(0,42,0)\) and \((0,0\), 42), then the value of the expression
\[\begin{aligned}& 3+\frac{x-11}{(y-19)^2(z-12)^2}+\frac{y-19}{(x-11)^2(z-12)^2} \\&+\frac{z-12}{(x-11)^2(y-19)^2}-\frac{x+y+z}{14(x-11)(y-19)(z-12)}\end{aligned}\]
is equal to:


[JEE Main 2021, 16 Mar (Shift 2)]

a

3

b

0

c

-45

d

39

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Q108
PYQ

Let a unit vector \(\overrightarrow{O P}\) make an angle \(\alpha, \beta, \gamma\) with the positive directions of the co-ordinate axes \(O X, O Y, O Z\) respectively, where \(\beta \in\left(0, \frac{\pi}{2}\right)\) if \(\overrightarrow{O P}\) is perpendicular to the plane through points \((1,2,3),(2,3,4)\) and \((1,5,7)\), then which one of the following is true?

[JEE Main 2023, 30 Jan (Shift 1)]

a

\(\alpha \in\left(\frac{\pi}{2}, \pi\right)\) and \(\gamma \in\left(\frac{\pi}{2}, \pi\right)\)

b

\(\alpha \in\left(0, \frac{\pi}{2}\right)\) and \(\gamma \in\left(0, \frac{\pi}{2}\right)\)

c

\(\alpha \in\left(\frac{\pi}{2}, \pi\right)\) and \(\gamma \in\left(0, \frac{\pi}{2}\right)\)

d

\(\alpha \in\left(0, \frac{\pi}{2}\right)\) and \(\gamma \in\left(\frac{\pi}{2}, \pi\right)\)

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Q109
PYQ

Let \(P\) be the plane passing through the line \(\frac{x-1}{1}=\frac{y-2}{-3}=\frac{z+5}{7}\) and the point \((2,4,-3)\). If the image of the point \((-1,3,4)\) in the plane \(P\) is \((\alpha, \beta, \gamma)\), then \(\alpha+\beta+\gamma\) is equal to

[JEE Main 2023, 8 Apr (Shift 2)]

a

12

b

11

c

9

d

10

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Q110
PYQ

Let \(P\) be the point of intersection of the line \(\frac{x+3}{3}=\frac{y+2}{1}=\frac{1-z}{2}\) and the plane \(x+y+z=2\). If the distance of the point \(P\) from the plane \(3 x-4 y+12 z=32\) is \(q\), then \(q\) and \(2 q\) are the roots of the equation

[JEE Main 2023, 10 Apr (Shift 1)]

a

\(x^2-18 x-72=0\)

b

\(x^2+18 x+72=0\)

c

\(x^2-18 x+72=0\)

d

\(x^2+18 x-72=0\)

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Q111
PYQ

The Distance of the point \((7,-3,-4)\) from the plane passing through the points \((2,-3,1),(-1,1,-2)\) and \((3,-4,2)\) is:

[JEE Main 2023, 24 Jan (Shift 1)]

a

4

b

5

c

\(5 \sqrt{2}\)

d

\(4 \sqrt{2}\)

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Q112
PYQ

If a plane passes through the points \((-1, k, 0),(2, k,-1)\), \((1,1,2)\) and is parallel to the line \(\frac{x-1}{1}=\frac{2 y+1}{2}=\frac{z+1}{-1}\), then the value of \(\frac{k^2+1}{(k-1)(k-2)}\) is

a

\(\frac{17}{5}\)

b

\(\frac{5}{17}\)

c

\(\frac{6}{13}\)

d

\(\frac{13}{6}\)

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Q113
PYQ

If for some \(\alpha\) and \(\beta\) in \(R\), the intersection of the following three planes
\[\begin{aligned}& x+4 y-2 z=1 \\& x+7 y-5 z=\beta \\& x+5 y+\alpha z=5\end{aligned}\] is a line in \(R ^3\), then \(\alpha+\beta\) is equal to :


[JEE Main 2020, 9 Jan (Shift 1)]

a

10

b

\( -10 \)

c

2

d

0

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Q114
PYQ

Consider the lines \(L_1\) and \(L_2\) given by
\(\begin{aligned}& L_1: \frac{x-1}{2}=\frac{y-3}{1}=\frac{z-2}{2} \\& L_2: \frac{x-2}{1}=\frac{y-2}{2}=\frac{z-3}{3}\end{aligned}\)

A line \(L_3\) having direction ratios \(1,-1,-2\), intersects \(L_1\) and \(L_2\) at the points \(P\) and \(Q\) respectively. Then the length of line segment \(P Q\) is

[JEE Main 2023, 25 Jan (Shift 1)]

a

\(2 \sqrt{6}\)

b

\(3 \sqrt{2}\)

c

\(4 \sqrt{3}\)

d

\(4\)

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Q115
PYQ

The shortest distance between the lines \(\frac{x-4}{4}=\frac{y+2}{5}=\frac{z+3}{3}\) and \(\frac{x-1}{3}=\frac{y-3}{4}=\frac{z-4}{2}\) is \(\quad\)

[JEE Main 2023, 8 Apr (Shift 1)]

a

\(6 \sqrt{3}\)

b

\(2 \sqrt{6}\)

c

\(6 \sqrt{2}\)

d

\(3 \sqrt{6}\)

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Q116
PYQ

The lines \(\frac{x-2}{1}=\frac{y-3}{1}=\frac{z-4}{-k}\) and \(\frac{x-1}{k}=\frac{y-4}{2}=\frac{z-5}{1}\) are coplanar if

a

\(k=3\) or -2

b

\(\mathrm{k}=0\) or -1

c

\(\mathrm{k}=1\) or -1

d

\(\mathrm{k}=0\) or -3

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Q117
PYQ

Let the equation of plane passing through the line of intersection of the planes \(x+2 y+a z=2\) and \(x-y+z=3\) be \(5 x-11 y+b z=6 a-1\). For \(c \in Z\), if the distance of this plane from the point \((a,-c, c)\) is \(\frac{2}{\sqrt{a}}\), then \(\frac{a+b}{c}\) is equal

[JEE Main 2023, 13 Apr (Shift 1)]

a

-5

b

5

c

-4

d

4

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Q118
PYQ

A vector \(\vec{v}\) in the first octant is inclined to the \(x\)-axis at \(60^{\circ}\), to the \(y\)-axis at \(45^{\circ}\) and to the \(z\)-axis at an acute angle. If a plane passing through the points \((\sqrt{2},-1,1)\) and \((a, b, c)\), is normal to \(\vec{v}\), then

a

\(\sqrt{2} a+b+c=1\)

b

\(a+b+\sqrt{2} c=1\)

c

\(a+\sqrt{2} b+c=1\)

d

\(\sqrt{2} a-b+c=1\)

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Q119
PYQ

Let the position vectors of two points \(P\) and \(Q\) be \(3 \hat{i}-\hat{j}+2 \hat{k}\) and \(\hat{i}+2 \hat{j}-4 \hat{k}\) respectively. Let \(R\) and \(S\) be two points such that the direction ratios of lines \(P R\) and \(Q S\) are \((4,-1,2)\) and \((-2,1,-2)\), respectively. Let lines \(P R\) and \(Q S\) intersect at \(T\). If the vector \(\overrightarrow{T A}\) is perpendicular to both \(\overrightarrow{P R}\) and \(\overrightarrow{Q S}\) and the length of vector \(\overrightarrow{T A}\) is \(\sqrt{5}\) units, then the modulus of a position vector of \(A\) is:

[JEE Main 2021, 16 Mar (Shift 1)]

a

\(\sqrt{227}\)

b

\(\sqrt{482}\)

c

\(\sqrt{5}\)

d

\(\sqrt{171}\)

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Q120
PYQ

Let the foot of perpendicular of the point \(P(3,-2,-9)\) on the plane passing through the points \((-1,-2,-3),(9,3,4)\), \((9,-2,1)\) be \(Q(\alpha, \beta, \gamma)\). Then the distance of \(Q\) from the origin is:

[JEE Main 2023, 15 Apr (Shift 1)]

a

\(\sqrt{29}\)

b

\(\sqrt{35}\)

c

\(\sqrt{42}\)

d

\(\sqrt{38}\)

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Q121
PYQ

Let the equation of the plane, that passes through the point \((1,4,-3)\) and contains the line of intersection of the planes \(3 x-2 y+4 z-7=0\) and \(x+5 y-2 z+9=0\), be \(\alpha x+\beta y+\) \(\gamma z+3=0\), then \(\alpha+\beta+\gamma\) is equal to:

[JEE Main 2021, 31 Aug (Shift 1)]

a

-15

b

15

c

-23

d

23

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Q122
PYQ

The plane, passing through the points \((0,-1,2)\) and \((-1,2,1)\) and parallel to the line passing through \((5,1,-7)\) and \((1,-1,-1)\) also passes through the point

[JEE Main 2023, 13 Apr (Shift 2)]

a

\((1,-2,1)\)

b

\((0,5,-2)\)

c

\((-2,5,0)\)

d

\((2,0,1)\)

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Q123
PYQ

Let a, b and c be distinct positive numbers. If the vectors \(a\hat{i}+a\hat{j}+c\hat{k},\hat{i}+\hat{k}\) and \(c\hat{i}+c\hat{j}+b\hat{k}\) are coplanar, then c is equal to:

[JEE Main 2021, 25 Jul (Shift 2)]

a

\(\frac{2}{\frac{1}{a}+\frac{1}{b}}\)

b

\(\frac{a+b}{2}\)

c

\(\frac{1}{a}+\frac{1}{b}\)

d

\(\sqrt{ab}\)

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Q124
PYQ

The distance of line \(3 y-2 z-1=0=3 x-z+4\) from the point \((2,-1,6)\) is:


[JEE Main 2021, 1 Sep (Shift 2)]

a

\(2 \sqrt{6}\)

b

\(\sqrt{26}\)

c

\(2 \sqrt{5}\)

d

\(4 \sqrt{2}\)

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Q125
PYQ

Let the shortest distance between the lines \(L: \frac{x-5}{-2}=\frac{y-\lambda}{0}=\frac{z+\lambda}{1}, \lambda \geq 0\) and \(L _1: x+1=y-1=4\) \(-z\) be \(2 \sqrt{6}\). If \((\alpha, \beta, \gamma)\) lies on \(L\), then which of the following is NOT possible?

[JEE Main 2023, 31 Jan (Shift 1)]

a

\(\alpha+2 \gamma=24\)

b

\(2\alpha+ \gamma=7\)

c

\(2 \alpha-\gamma=9\)

d

\(\alpha-2 \gamma=19\)

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Q126
PYQ

Let the line passing through the points, \(P(2,-1,2)\) and \(Q(5,3,4)\) meet the plane \(x-y+z=4\) at the point \(R\). Then the distance of the point \(R\) from the plane \(x+2 y+3 z+2=0\) measured parallel to the line \(\frac{x-7}{2}=\frac{y+3}{2}=\frac{z-2}{1}\) is equal to

[JEE Main 2023, 11 Apr (Shift 2)]

a

\(\sqrt{31}\)

b

\(\sqrt{29}\)

c

\(\sqrt{61}\)

d

\(3\)

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Q127
PYQ

Let the foot of perpendicular from a point \(P(1,2\), \(-1)\) to the straight line \(L: \frac{x}{1}=\frac{y}{0}=\frac{z}{-1}\) be \(N\). Let a line be drawn from \(P\) parallel to the plane \(x+y+\) \(2 z=0\) which meets \(L\) at point \(Q\). If \(\alpha\) is the acute

angle between the lines \(P N\) and \(P Q\), then \(\cos \alpha\) is equal to:

[JEE Main 2021, 25 Jul (Shift 1)]

a

\(\frac{1}{\sqrt{5}}\)

b

\(\frac{\sqrt{3}}{2}\)

c

\(\frac{1}{\sqrt{3}}\)

d

\(\frac{1}{2 \sqrt{3}}\)

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Q128
PYQ

\(A\) plane passes through the points \(A(1,2,3), B(2,3,1)\) and \(C(2,4,2)\). If \(O\) is the origin and \(P\) is \((2,-1,1)\), then the projection of \(\overline{ OP }\) on this plane is of length:

[JEE Main 2021, 25 Feb (Shift 2)]

a

\(\sqrt{\frac{2}{5}}\)

b

\(\sqrt{\frac{2}{3}}\)

c

\(\sqrt{\frac{2}{7}}\)

d

\(\sqrt{\frac{2}{11}}\)

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Q129
PYQ

Consider the lines \(L_1\) and \(L_2\) given by
\[\begin{aligned}& L_1: \frac{x-1}{2}=\frac{y-3}{1}=\frac{z-2}{2} \\& L_2: \frac{x-2}{1}=\frac{y-2}{2}=\frac{z-3}{3}\end{aligned}\]

A line \(L_3\) having direction ratios \(1,-1,-2\), intersects \(L_1\) and \(L_2\) at the points \(P\) and \(Q\) respectively. Then the length of line segment \(P Q\) is

a

\(2 \sqrt{6}\)

b

\(3 \sqrt{2}\)

c

\(4 \sqrt{3}\)

d

4

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Q130
PYQ

The shortest distance between the lines \(x+1=2 y=-12 z\) and \(x=y+2=6 z-6\) is

a

\(2\)

b

\(3\)

c

\(\frac{5}{2}\)

d

\(\frac{3}{2}\)

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Q131
PYQ

Let \(P\) be a plane \(l x+m y+n z=0\) containing the line, \(\frac{1-x}{1}=\frac{y+4}{2}=\frac{z+2}{3}\). If plane \(P\) divides the line segment \(A B\) joining points \(A(-3,-6,1)\) and \(B(2,4,-3)\) in ratio \(k: 1\), then the value of \(k\) is equal to:

[JEE Main 2021, 16 Mar (Shift 1)]

a

4

b

2

c

1.5

d

3

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Q132
PYQ

The shortest distance between the lines \(x+1=2 y=-12 z\) and \(x=y+2=6 z-6\) is

[JEE Main 2023, 25 Jan (Shift 2)]

a

2

b

3

c

\(\frac{5}{2}\)

d

\(\frac{3}{2}\)

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Q133
PYQ

For real numbers \(\alpha\) and \(\beta \neq 0\), if the point of intersection of the straight lines \(\frac{x-\alpha}{1}=\frac{y-1}{2}=\frac{z-1}{3}\) and \(\frac{x-4}{\beta}=\frac{y-6}{3}=\frac{z-7}{3}\) lies on the plane \(x+2 y-z=8\), then \(\alpha-\beta\) is equal to:

[JEE Main 2021, 27 Jul (Shift 2)]

a

5

b

3

c

7

d

9

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Q134
PYQ

The shortest distance between the lines \(\frac{x-4}{4}=\frac{y+2}{5}=\frac{z+3}{3}\) and \(\frac{x-1}{3}=\frac{y-3}{4}=\frac{z-4}{2}\) is \(\quad\)

a

\(6 \sqrt{3}\)

b

\(2 \sqrt{6}\)

c

\(6 \sqrt{2}\)

d

\(3 \sqrt{6}\)

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Q135
PYQ

The foot of perpendicular of the point \((2,0,5)\) on the line \(\frac{x+1}{2}=\frac{y-1}{5}=\frac{z+1}{-1}\) is \((\alpha, \beta, \gamma)\). Then.
Which of the following is NOT correct?

[JEE Main 2023, 25 Jan (Shift 2)]

a

\(\frac{\alpha \beta}{\gamma}=\frac{4}{15}\)

b

\(\frac{\alpha}{\beta}=-8\)

c

\(\frac{\beta}{\gamma}=-5\)

d

\(\frac{\gamma}{\alpha}=\frac{5}{8}\)

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Q136
PYQ

The distance of the point \((1,1,9)\) from the point of intersection of the line \(\frac{x - 3}{1} = \frac{y - 4}{2} = \frac{z - 5}{2}\) and the plane \(x + y + z = 17\) is:

[JEE Main 2021, 24 Feb (Shift 1)]

a

\(2\)

b

\(\sqrt {38}\)

c

\(38\)

d

\(19\)

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Q137
PYQ

Let \((\alpha, \beta, \gamma)\) be the image of the point \(P(2,3,5)\) in the plane \(2 x+y-3 z=6\). Then \(\alpha+\beta+\gamma\) is equal to

[JEE Main 2023, 11 Apr (Shift 1)]

a

10

b

5

c

12

d

9

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Q138
PYQ

The equation of the plane which contains the \(y\)-axis and passes through the point \((1,2,3)\) is :

[JEE Main 2021, 17 Mar (Shift 1)]

a

\(x+3z=0\)

b

\(3x-z=0\)

c

\(x+3z=10\)

d

\(3x-z=6\)

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Q139
PYQ

Let P be the plane passing through the point (1,2,3) and the line of intersection of the planes \(\vec{r}\cdot (\hat{i}+\hat{j}+4\hat{k})=16\) and \(\vec{r}\cdot (-\hat{i}+\hat{j}+\hat{k})=6\).
Then which of the following points does NOT lie on P ?

[JEE Main 2021, 26 Aug (Shift 2)]

a

(3,3,2)

b

(6,-6,2)

c

(-8,8,6)

d

(4,2,2)

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Q140
PYQ

Let \(P\) be the plane passing through the point \((1,2,3)\) and the line of intersection of the planes \(\vec{r} \cdot(\hat{i}+\hat{j}+4 \hat{k})=16\) and \(\vec{r} \cdot(-\hat{i}+\hat{j}+\hat{k})=6\). Then which of the following points does NOT lie on \(P\) ?

[JEE Main 2021, 26 Aug (Shift 2)]

a

(3,3,2)

b

(6,-6,2)

c

(-8,8,6)

d

(4,2,2)

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Q141
PYQ

The vector equation of the plane passing through the intersection of the planes \(\vec{r} \cdot(\hat{i}+\hat{j}+\hat{k})=1\) and \(\vec{r} \cdot(\hat{i}-2 \hat{j})=-2\), and the point \((1,0,2)\) is:


[JEE Main 2021, 24 Feb (Shift 2)]

a

\(\vec{r} \cdot(\hat{i}+7 \hat{j}+3 \hat{k})=\frac{7}{3}\)

b

\(\vec{r} \cdot(3 \hat{i}+7 \hat{j}+3 \hat{k})=7\)

c

\(\vec{r} \cdot(\hat{i}-7 \hat{j}+3 \hat{k})=\frac{7}{3}\)

d

\(\vec{r} \cdot(\hat{i}+7 \hat{j}+3 \hat{k})=7\)

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Q142
PYQ

Let the line \(\frac{x}{1}=\frac{6-y}{2}=\frac{z+8}{5}\) intersect the lines \(\frac{x-5}{4}=\frac{y-7}{3}=\frac{z+2}{1}\) and \(\frac{x+3}{6}=\frac{3-y}{3}=\frac{z-6}{1}\) at the points \(A\) and \(B\) respectively. Then the distance of the midpoint of the line segment \(A B\) from the plane \(2 x-2 y+z\) \(=14\) is

[JEE Main 2023, 10 Apr (Shift 2)]

a

4

b

\(\frac{10}{3}\)

c

3

d

\(\frac{11}{3}\)

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Q143
PYQ

Consider the three planes \(P_{1}: 3 x+15 y+21 z=9\), \(P_{2}: x-3 y-z=5\) and \(P_{3}: 2 x+10 y+14 z=5\). Then, which one of the following is true?

[JEE Main 2021, 26 Feb (Shift 1)]

a

\( P_{1} \) and \( P_{2} \) are parallel.

b

\( P_{1}, P_{2} \) and \( P_{3} \) all are parallel.

c

\( P_{1} \) and \( P_{3} \) are parallel.

d

\( P_{2} \) and \( P_{3} \) are parallel.

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Q144
PYQ

Let the system of linear equations
\(\begin{aligned}& -x+2 y-9 z=7 \\& -x+3 y+7 z=9 \\& -2 x+y+5 z=8 \\& -3 x+y+13 z=\lambda\end{aligned}\)
has a unique solution \(x=\alpha, y=\beta, z=\gamma\). Then the distance of the point \((\alpha, \beta, \gamma)\) from the plane \(2 x-2 y+z=\lambda\) is

[JEE Main 2023, 15 Apr (Shift 1)]

a

9

b

11

c

13

d

7

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Q145
PYQ

Let the equation of plane passing through the line of intersection of the planes \(x+2 y+a z=2\) and \(x-y+z=3\) be \(5 x-11 y+b z=6 a-1\). For \(c \in Z\), if the distance of this plane from the point \((a,-c, c)\) is \(\frac{2}{\sqrt{a}}\), then \(\frac{a+b}{c}\) is equal to:

a

-5

b

5

c

-4

d

4

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Q146
PYQ

Let the equation of the plane, that passes through the point \(\left( 1,4, - 3 \right)\) and contains the line of intersection of the planes \(3x - 2y + 4z - 7 = 0\) and \(x + 5y - 2z + 9 = 0\), be \(\alpha x\ + \beta y + \gamma z + 3 = 0\) then \(\alpha + \beta + \gamma\) is equal to?

[JEE Main 2021, 31 Aug (Shift 1)]

a

\(-15\)

b

\(15\)

c

\(-23\)

d

\(23\)

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Q147
PYQ

Let the plane passing through the point \((-1,0,-2)\) and perpendicular to each of the planes \(2x+y-z=2\) and \(x-y-z=3\) be \(ax+by+cz+8=0\). Then the value of a+b+c is equal to:

[JEE Main 2021, 27 Jul (Shift 1)]

a

3

b

8

c

5

d

4

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Q148
PYQ

The distance from the point \((3,4,5)\) to the point where the line \(\frac{x-3}{1}=\frac{y-4}{2}=\frac{z-5}{2}\) meets the plane \(\mathrm{x}+\mathrm{y}+\mathrm{z}=17\) is

a

1

b

2

c

3

d

\(\sqrt{2}\)

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Q149
PYQ

Let the system of linear equations \(-x+2 y-9 z=7\), \(-x+3 y+7 z=9\), \(-2 x+y+5 z=8\) and \(-3 x+y+13 z=\lambda\) has a unique solution \(x=\alpha, y=\beta, z=\gamma\). Then the distance of the point \((\alpha, \beta, \gamma)\) from the plane \(2 x-2 y+z=\lambda\) is

[JEE Main 2023, 15 Apr (Shift 1)]

a

9

b

11

c

13

d

7

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Q150
PYQ

The lines \(x=ay–1=z–2\) and \(x=3y–2=bz–2,(ab\neq 0)\) are coplanar, if:

[JEE Main 2021, 20 Jul (Shift 2)]

a

\(a=2,b=2\)

b

\(b=1,a\in R–\left\{0\right\}\)

c

\(a=2,b=3\)

d

\(a=1,b\in R–\left\{0\right\}\)

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Q151
PYQ

Let \(a, b \in R\). If the mirror image of the point \(P(a, 6,9)\) with respect to the line \(\frac{x-3}{7}=\frac{y-2}{5}=\frac{z-1}{-9}\) is (20, \(b,-a-9)\), then \(|a+b|\) is equal to:

[JEE Main 2021, 24 Feb (Shift 2)]

a

90

b

86

c

84

d

88

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Q152
PYQ

Let \(S\) be the set of all values of \(\lambda\), for which the shortest distance between the lines \(\frac{x-\lambda}{0}=\frac{y-3}{4}=\frac{z+6}{1}\) and \(\frac{x+\lambda}{3}=\frac{y}{-4}=\frac{z-6}{0}\) is \(13\) . Then \(8\left|\sum_{\lambda \in S} \lambda\right|\) is equal to

[JEE Main 2023, 15 Apr (Shift 1)]

a

304

b

308

c

306

d

302

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Q153
PYQ

Let \(P\) be the plane passing through the line \(\frac{x-1}{1}=\frac{y-2}{-3}=\frac{z+5}{7}\) and the point \((2,4,-3)\). If the image of the point \((-1,3,4)\) in the plane \(P\) is \((\alpha, \beta, \gamma)\), then \(\alpha+\beta+\gamma\) is equal to

[JEE Main 2023, 08 Apr (Shift 2)]

a

12

b

11

c

9

d

10

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Q154
PYQ

If the equation of the plane containing the line x + 2y + 3z – 4 = 0 = 2x + y – z + 5 and perpendicular to the plane \(\vec{r}=\left(\hat{i}−\hat{j}\right)+\lambda \left(\hat{i}+\hat{j}+\hat{k}\right)+\mu \left(\hat{i}−2\hat{j}+3\hat{k}\right)\) is ax + by + cz = 4, then (ab + c) is equal to

[JEE Main 2023, 08 Apr (Shift 1)]

a

18

b

22

c

20

d

24

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Q155
PYQ

Let \(Q\) be the cube with the set of vertices \(\left\{\left(x_1, x_2, x_3\right)\right\}\) \(\in R ^3: x_1, x_2, x_3\{0,1\}\). Let \(F\) be the set of all \(F\) twelve lines containing the diagonals of the six faces of the cube \(Q\). Let \(S\) be the set of all four lines containing the main diagonals of the cube \(Q\); for instance, the line passing through the vertices \((0,0,0)\) and \((1,1,1)\) is in \(S\). For lines \(\ell_1\) and \(\ell_2\), let \(d\left(\ell_1, \ell_2\right)\) denote the shortest distance between them. Then the maximum value of \(d \left(\ell_1, \ell_2\right)\), as \(\ell_1\) varies over \(F\) and \(\ell_2\) varies over \(S\), is

[JEE Advanced 2023]

a

\(\frac{1}{\sqrt{6}}\)

b

\(\frac{1}{\sqrt{8}}\)

c

\(\frac{1}{\sqrt{3}}\)

d

\(\frac{1}{\sqrt{12}}\)

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Q156
PYQ

The equation of the plane which contains the \(y\)-axis and passes through the point \((1,2,3)\) is:

[JEE Main 2021, 17 Mar (Shift 1)]

a

\(x+3 z=10\)

b

\(3 x+3 z=6\)

c

\(3 x-z=0\)

d

\(x+3 z=0\)

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Q157
PYQ

A plane \(P\) contains the line \(x+2 y+3 z+1=0=x-y-z-6\), and is perpendicular to the plane \(-2 x+y+z+8=0\). Then which of the following points lies on \(P\) ?

[JEE Main 2021, 26 Aug (Shift 1)]

a

\((2,-1,1)\)

b

\((0,1,1)\)

c

\((-1,1,2)\)

d

\((1,0,1)\)

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