If $\frac{1}{n+1}{}^{n}C_{n}+\frac{1}{n}{}^{n}C_{n-1}+\ldots +\frac{1}{2}{}^{n}C_{1}+{}^{n}C_{0}=\frac{1023}{10}$ then $n$ is equal to: [JEE Main 2023, 12 Apr (Shift 1)]

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If \(\frac{1}{n+1}{}^{n}C_{n}+\frac{1}{n}{}^{n}C_{n-1}+\ldots +\frac{1}{2}{}^{n}C_{1}+{}^{n}C_{0}=\frac{1023}{10}\) then…

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