If $y=\sqrt{\left(\frac{1+\cos 2 \theta}{1-\cos 2 \theta}\right)}$, then $\frac{d y}{d \theta}$ at $\boldsymbol{\theta}=\frac{3 \pi}{4}$ is :

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If \(y=\sqrt{\left(\frac{1+\cos 2 \theta}{1-\cos 2 \theta}\right)}\), then \(\frac{d y}{d \theta}\) at \(\boldsymbol{\th…