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If the time period of a two meter long simple pendulum is \(2 s\), the acceleration due to gravity at the place where pe…

Q1

If the time period of a two meter long simple pendulum is \(2 s\), the acceleration due to gravity at the place where pendulum is executing S.H.M. is:

a

\(9.8 ms ^{-2}\)

b

\(16 m / s ^2\)

c

\(2 \pi^2 ms ^{-2}\)

d

\(\pi^2 ms ^{-2}\)

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