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The shortest distance between the lines x + 1 = 2 y = –12 z and x = y + 2 = 6 z – 6 is

Q1

The shortest distance between the lines x + 1 = 2y = –12z and x = y + 2 = 6z – 6 is

a

2

b

3

c

\(\frac{5}{2}\)

d

\(\frac{3}{2}\)

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