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The equation of the line through the point \((0,1,2)\) and perpendicular to the line \(\frac{x-1}{2}=\frac{y+1}{3}=\frac…

Q1

The equation of the line through the point \((0,1,2)\) and perpendicular to the line \(\frac{x-1}{2}=\frac{y+1}{3}=\frac{z-1}{-2}\) is:

[JEE Main 2021, 25 Feb (Shift 1)]

a

\(\frac{x}{3}=\frac{y-1}{4}=\frac{z-2}{3}\)

b

\(\frac{x}{-3}=\frac{y-1}{4}=\frac{z-2}{3}\)

c

\(\frac{x}{3}=\frac{y-1}{4}=\frac{z-2}{-3}\)

d

\(\frac{x}{3}=\frac{y-1}{-4}=\frac{z-2}{3}\)

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