🛠️ JEE🧲 Physics

Surface tension of a soap bubble is \(2.0 \times 10^{-2} \mathrm{Nm}^{-1}\). Work done to increase the radius of soap bu…

Q1

Surface tension of a soap bubble is \(2.0 \times 10^{-2} \mathrm{Nm}^{-1}\). Work done to increase the radius of soap bubble from \(3.5 \mathrm{~cm}\) to \(7 \mathrm{~cm}\) will be : [Use \(\pi=\frac{22}{7}\) ]

[JEE Main 2023, 29 Jan (Shift 1)]

a

\(0.72 \times 10^{-4} \mathrm{~J}\)

b

\(5.76 \times 10^{-4} \mathrm{~J}\)

c

\(18.48 \times 10^{-4} J\)

d

\(9.24 \times 10^{-4} J\)

🔒
Answer & explanation — PYQ Pass

Options are free to see. Unlock the correct answer and full explanation with Pass.

Unlock · ₹149

Practice more JEE Physics PYQs

See every question on Mechanical Properties of Fluids, or browse the full JEE question bank.

See all questions on Mechanical Properties of Fluids →