🛠️ JEE➗ Maths

If \(x y+y^2=\tan x+y\), then find \(\frac{d y}{d x}\) is

\(\frac{\sec ^2 x}{x+2 y}\)

\(\frac{\sec ^2 x-y}{(x+2 y-1)}\)

\((x+2 y-1) \sec ^2 x\)

\(\sec ^2 x \cdot y\)

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