For the reaction A \(\to\)B , the rate constant k ( in s -1 ), is given by log k = 20.35 - \(\frac{(2.47\times {10}^{3})…
Q1
For the reaction A \(\to\)B , the rate constant k ( in s-1), is given by log k = 20.35 - \(\frac{(2.47\times {10}^{3})}{\mathrm{T}}\). The energy of activation in kJ/mol is ____. (Nearest integer)
[Given R- 8.314 J/K/mol]
[JEE Main 2021, 31 Aug (Shift 2)]
🔒
Answer & explanation — PYQ Pass
Unlock · ₹149
Options are free to see. Unlock the correct answer and full explanation with Pass.
Practice more JEE Chemistry PYQs
See every question on Chemical Kinetics, or browse the full JEE question bank.
See all questions on Chemical Kinetics →