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🛠️ JEE🧪 Chemistry

\(\mathrm{Co}{({\mathrm{NH}}_{3})}_{\mathrm{x}}{\mathrm{Cl}}_{3}\) has 0.1 molal. 100% dissociation\(∆{\mathrm{T}}_{\mat…

Q1

\(\mathrm{Co}{({\mathrm{NH}}_{3})}_{\mathrm{x}}{\mathrm{Cl}}_{3}\) has 0.1 molal. 100% dissociation\(∆{\mathrm{T}}_{\mathrm{f}}=0.558({\mathrm{K}}_{\mathrm{f}}=1.86)\). Then formula of the compound is

(JEE mains memory based shift-1 23/01/2025)

a

\(\left[\mathrm{Co}{({\mathrm{NH}}_{3})}_{4}{\mathrm{Cl}}_{2}\right]\)

b

\(\left[\mathrm{Co}{({\mathrm{NH}}_{3})}_{2}{\mathrm{Cl}}_{4}\right]\)

c

\(\left[\mathrm{Co}{({\mathrm{NH}}_{3})}_{5}\mathrm{Cl}\right]C{l}_{2}\)

d

\(\left[\mathrm{Co}{({\mathrm{NH}}_{3})}_{4}{\mathrm{Cl}}_{2}\right]C{l}_{2}\)

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