For a certain metal, when monochromatic light of wavelength \(\lambda\) is incident, the stopping potential for photoelectrons is \(3{V}_{0}\). When the same metal is illuminated by light of wavelength \(2\lambda\), then the stopping potential becomes \({V}_{0}\). The threshold wavelength for photoelectric emission for the given metal is \(\alpha \lambda\). The value of \(\alpha\) is

[JEE Main 2026, 2 Apr (Shift 1)]

Question

For a certain metal, when monochromatic light of wavelength \(\lambda\) is incident, the stopping potential for photoelectrons is \(3{V}_{0}\). When the same metal is illuminated by light of wavelength \(2\lambda\), then the stopping potential becomes \({V}_{0}\). The threshold wavelength for photoelectric emission for the given metal is \(\alpha \lambda\). The value of \(\alpha\) is

[JEE Main 2026, 2 Apr (Shift 1)]

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