Let the line L be $\frac{x-1}{1}=\frac{y-4}{3}=\frac{z-7}{5}$ and foot of perpendicular from (1,-2,-1) to L is $(\alpha ,\beta ,\gamma )$, then $\alpha +\beta +\gamma$ is :

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Let the line L be \(\frac{x-1}{1}=\frac{y-4}{3}=\frac{z-7}{5}\) and foot of perpendicular from (1,-2,-1) to L is \((\alp…

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