If \(\sin x+{\sin }^{2}x=1,x\in \left(0,\frac{\pi }{2}\right)\), then \(\left({\cos }^{12}x+{\tan }^{12}x\right)+3\left(…

If \(\sin x+{\sin }^{2}x=1,x\in \left(0,\frac{\pi }{2}\right)\), then

\(\left({\cos }^{12}x+{\tan }^{12}x\right)+3\left({\cos }^{10}x+{\tan }^{10}x+{\cos }^{8}x+{\tan }^{8}x\right)+\left({\cos }^{6}x+{\tan }^{6}x\right)\) is equal to:

[JEE Main 2025, 29 Jan (Shift 2)]