YESPYQ Start Practice
🛠️ JEE🧲 Physics

A photo-emissive substance is illuminated with a radiation of wavelength \({\lambda }_{\mathrm{i}}\) so that it releases…

Q1

A photo-emissive substance is illuminated with a radiation of wavelength \({\lambda }_{\mathrm{i}}\) so that it releases electrons with de-Broglie wavelength \({\lambda }_{\mathrm{e}}\). The longest wavelength of radiation that can emit photoelectron is \({\lambda }_{0}\). Expression for de-Broglie wavelength is given by :
( m : mass of the electron, h : Planck's constant and c : speed of light)

[JEE Main 2025, 7 Apr (Shift 2)]

a

\({\lambda }_{\mathrm{e}}=\sqrt{\frac{\mathrm{h}}{2\mathrm{mc}\left(\frac{1}{{\lambda }_{\mathrm{i}}}-\frac{1}{{\lambda }_{0}}\right)}}\)

b

\({\lambda }_{e}=\sqrt{\frac{h{\lambda }_{0}}{2mc}}\)

c

\({\lambda }_{e}=\frac{h}{\sqrt{2mc\left(\frac{1}{{\lambda }_{i}}-\frac{1}{{\lambda }_{0}}\right)}}\)

d

\({\lambda }_{e}=\sqrt{\frac{h{\lambda }_{i}}{2mc}}\)

🔒
Answer & explanation — PYQ Pass

Options are free to see. Unlock the correct answer and full explanation with Pass.

Unlock · ₹149
← Previous questionNext question →

Practice more JEE Physics PYQs

See every question on Dual Nature of Radiation and Matter, or browse the full JEE question bank.

See all questions on Dual Nature of Radiation and Matter →