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A force \(\mathrm{F}=\alpha +{\mathrm{βx}}^{2}\) acts on an object in the x -direction. The work done by the force is 5 …

Q1

A force \(\mathrm{F}=\alpha +{\mathrm{βx}}^{2}\) acts on an object in the x -direction. The work done by the force is 5 J when the object is displaced by 1 m. If the constant \(\alpha =1\mathrm{N}\) then \(\beta\) will be

[JEE Main 2025, 24 Jan (Shift 1)]

a

\(10\mathrm{N}/{\mathrm{m}}^{2}\)

b

\(8\mathrm{N}/{\mathrm{m}}^{2}\)

c

\(15\mathrm{N}/{\mathrm{m}}^{2}\)

d

\(12\mathrm{N}/{\mathrm{m}}^{2}\)

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