🛠️ JEE➗ Maths

A circle is drawn with the two foci of an ellipse \(\frac{{x}^{2}}{{a}^{2}}+\frac{{y}^{2}}{{b}^{2}}=1\) as the ends of t…

Q1

A circle is drawn with the two foci of an ellipse \(\frac{{x}^{2}}{{a}^{2}}+\frac{{y}^{2}}{{b}^{2}}=1\) as the ends of the diameter. What is the equation of the circle?

a

\({x}^{2}+{y}^{2}={a}^{2}+{b}^{2}\)

b

\({x}^{2}+{y}^{2}={a}^{2}−{b}^{2}\)

c

\({x}^{2}+{y}^{2}=2\left({a}^{2}+{b}^{2}\right)\)

d

\({x}^{2}+{y}^{2}=2\left({a}^{2}−{b}^{2}\right)\)

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