The square of the distance of the point \((-2,-8,6)\) from the line \(\frac{x-1}{1}=\frac{y-1}{2}=\frac{z}{-1}\) along the line \(\frac{x+5}{1}=\frac{y+5}{-1}=\frac{z}{2}\)is equal to:

[JEE Main 2026, 4 Apr (Shift 1)]

Question

The square of the distance of the point \((-2,-8,6)\) from the line \(\frac{x-1}{1}=\frac{y-1}{2}=\frac{z}{-1}\) along the line \(\frac{x+5}{1}=\frac{y+5}{-1}=\frac{z}{2}\)is equal to:

[JEE Main 2026, 4 Apr (Shift 1)]

YESPYQ · Accepted Answer

Options are free to see. Unlock the correct answer and full explanation with PYQ Pass.

The square of the distance of the point \((-2,-8,6)\) from the line \(\frac{x-1}{1}=\frac{y-1}{2}=\frac{z}{-1}\) along t…

Practice more JEE Maths PYQs