A particle is projected with velocity u so that its horizontal range is three times the maximum height attained by it. The horizontal range of the projectile is given as \(\frac{n{u}^{2}}{25g}\), where value of n is :
(Given ' g ' is the acceleration due to gravity).

[JEE Main 2025, 3 Apr (Shift 2)]

Question

A particle is projected with velocity u so that its horizontal range is three times the maximum height attained by it. The horizontal range of the projectile is given as \(\frac{n{u}^{2}}{25g}\), where value of n is :
(Given ' g ' is the acceleration due to gravity).

[JEE Main 2025, 3 Apr (Shift 2)]

YESPYQ · Accepted Answer

Options are free to see. Unlock the correct answer and full explanation with PYQ Pass.

A particle is projected with velocity u so that its horizontal range is three times the maximum height attained by it. T…

Practice more JEE Physics PYQs