Motion in a Plane
58 JEE Physics previous year questions on Motion in a Plane — options free on every question; 6 include the answer & explanation free, the rest unlock with PYQ Pass.
A ball of mass 100 g is projected with velocity \(20\mathrm{m}/\mathrm{s}\) at \(60^\circ\) with horizontal. The decrease in kinetic energy of the ball during the motion from point of projection to highest point is
[JEE Main 2025, 22 Jan (Shift 2)]
15 J
\(K{E}_{\text{initial }}=\frac{1}{2}m{v}^{2}\\ K{E}_{\text{initial }}=\frac{1}{2}\times 0.1\times (20{)}^{2}=20J\\ K{E}_{\text{final }}=\frac{1}{2}m{v}_{x}^{2}\\ K{E}_{\text{final }}=\frac{1}{2}\times 0.1\times (10{)}^{2}=5J\text{ Decrease in Kinetic Energy }\\ \Delta KE=K{E}_{\text{initial }}-K{E}_{\text{final }}\\ \Delta KE=20-5=15J\)
Two projectiles are fired from ground with same initial speeds from same point at angles \(\left(45^\circ +\alpha \right)\) and \(\left(45^\circ -\alpha \right)\) with horizontal direction. The ratio of their times of flights is
[JEE Main 2025, 7 Apr (Shift 1)]
\(\frac{1+\tan \alpha }{1-\tan \alpha }\)
Angles of projection
\({\theta }_{1}=45+\alpha\)
\({\theta }_{2}=45-\alpha\)
Time of flight formula
\(T=\frac{2v\sin \theta }{g}\)
Ratio of times of flight
\(\frac{{T}_{1}}{{T}_{2}}=\frac{\sin (45+\alpha )}{\sin (45-\alpha )}\)
Using trigonometric identities
\(\frac{{T}_{1}}{{T}_{2}}=\frac{\frac{1}{\sqrt{2}}\cos \alpha +\frac{1}{\sqrt{2}}\sin \alpha }{\frac{1}{\sqrt{2}}\cos \alpha -\frac{1}{\sqrt{2}}\sin \alpha }\)
Simplifying
\(\frac{{T}_{1}}{{T}_{2}}=\frac{\cos \alpha +\sin \alpha }{\cos \alpha -\sin \alpha }\)
Final ratio
\(\frac{{T}_{1}}{{T}_{2}}=\frac{1+\tan \alpha }{1-\tan \alpha }\)
Two particles are projected with the same velocity but at different projection angles: \(\left(\frac{\pi }{4}+\alpha \right)\) and \(\left(\frac{\pi }{4}-\alpha \right)\). Determine the ratio of their maximum heights.
\(\frac{1+\sin 2\alpha }{1−\sin 2\alpha }\)
The maximum height of a projectile is given by:
\(H=\frac{{u}^{2}{\sin }^{2}\theta }{2g}\)
where:
- \(u\) is the initial velocity,
- \(\theta\) is the angle of projection,
- \(g\) is the acceleration due to gravity.
The two angles of projection given are:
- \({\theta }_{1}=\alpha +\frac{\pi }{4}\)
- \({\theta }_{2}=\alpha −\frac{\pi }{4}\)
Using the formula for maximum height:
\({H}_{1}=\frac{{u}^{2}{\sin }^{2}(\alpha +\pi \mathrm{/}4)}{2g}\)
\({H}_{2}=\frac{{u}^{2}{\sin }^{2}(\alpha −\pi \mathrm{/}4)}{2g}\)
Step 3: Taking the RatioThe required ratio is:
\(\frac{{H}_{1}}{{H}_{2}}=\frac{{\sin }^{2}(\alpha +\pi \mathrm{/}4)}{{\sin }^{2}(\alpha −\pi \mathrm{/}4)}\)
Using the sine angle addition and subtraction formulas:
\(\sin (\alpha +\pi \mathrm{/}4)=\frac{\sin \alpha +\cos \alpha }{\sqrt{2}}\)
\(\sin (\alpha −\pi \mathrm{/}4)=\frac{\sin \alpha −\cos \alpha }{\sqrt{2}}\)
Squaring both:
\({\sin }^{2}(\alpha +\pi \mathrm{/}4)=\frac{(\sin \alpha +\cos \alpha {)}^{2}}{2}\)
\({\sin }^{2}(\alpha −\pi \mathrm{/}4)=\frac{(\sin \alpha −\cos \alpha {)}^{2}}{2}\)
Thus, the ratio simplifies to:
\(\frac{{H}_{1}}{{H}_{2}}=\frac{(\sin \alpha +\cos \alpha {)}^{2}}{(\sin \alpha −\cos \alpha {)}^{2}}\)
Using the identity:
\((\sin \alpha +\cos \alpha {)}^{2}=1+\sin 2\alpha\)
\((\sin \alpha −\cos \alpha {)}^{2}=1−\sin 2\alpha\)
\(\frac{{H}_{1}}{{H}_{2}}=\frac{1+\sin 2\alpha }{1−\sin 2\alpha }\)
Step 4: Selecting the Correct OptionComparing with the given options, the correct answer is:
\(A\ \frac{1+\sin 2\alpha }{1−\sin 2\alpha }\)
Two projectiles are fired with same initial speed from same point on ground at angles of \(\left(45^\circ -\alpha \right)\) and \(\left(45^\circ +\alpha \right)\), respectively, with the horizontal direction. The ratio of their maximum heights attained is :
[JEE Main 2025, 29 Jan (Shift 1)]
\(\frac{1-\sin 2\alpha }{1+\sin 2\alpha }\)
\(\frac{{\left({H}_{\max }\right)}_{1}}{{\left({H}_{\max }\right)}_{2}}=\frac{{u}^{2}{\sin }^{2}(45-\alpha )}{{u}^{2}{\sin }^{2}(45+\alpha )}\\ =\frac{{\left(\frac{1}{\sqrt{2}}\cos \alpha -\frac{1}{\sqrt{2}}\sin \alpha \right)}^{2}}{{\left(\frac{1}{\sqrt{2}}\cos \alpha +\frac{1}{\sqrt{2}}\sin \alpha \right)}^{2}}\\ =\frac{1-\sin 2\alpha }{1+\sin 2\alpha }\)
If the radius of curvature of the path of two particles of same mass are in the ratio 3:4, then in order to have constant centripetal force, their velocities will be in the ratio of:
\(\sqrt{3}:2\)
\(\frac{{r}_{1}}{{r}_{2}}=\frac{3}{4}\)
As centripetal force F \(=\frac{m{v}^{2}}{r}\)
In order to have constant (same in this question) centripetal force
$$\begin{aligned}& F_1=F_2 \\& \frac{m_1 v_1^2}{r_1}=\frac{m_2 v_2^2}{r_2} \\& \Rightarrow \frac{v_1}{v_2}=\sqrt{\frac{r_1}{r_2}}=\frac{\sqrt{3}}{2}\end{aligned}$$
Two particles are projected with the same velocity but at different projection angles: \(\left(\frac{\pi }{4}+\alpha \right)\) and \(\left(\frac{\pi }{4}-\alpha \right)\). Determine the ratio of their maximum heights.
\(\frac{1+\sin 2\alpha }{1−\sin 2\alpha }\)
The maximum height of a projectile is given by:
\(H=\frac{{u}^{2}{\sin }^{2}\theta }{2g}\)
where:
- \(u\) is the initial velocity,
- \(\theta\) is the angle of projection,
- \(g\) is the acceleration due to gravity.
The two angles of projection given are:
- \({\theta }_{1}=\alpha +\frac{\pi }{4}\)
- \({\theta }_{2}=\alpha −\frac{\pi }{4}\)
Using the formula for maximum height:
\({H}_{1}=\frac{{u}^{2}{\sin }^{2}(\alpha +\pi \mathrm{/}4)}{2g}\)
\({H}_{2}=\frac{{u}^{2}{\sin }^{2}(\alpha −\pi \mathrm{/}4)}{2g}\)
Step 3: Taking the RatioThe required ratio is:
\(\frac{{H}_{1}}{{H}_{2}}=\frac{{\sin }^{2}(\alpha +\pi \mathrm{/}4)}{{\sin }^{2}(\alpha −\pi \mathrm{/}4)}\)
Using the sine angle addition and subtraction formulas:
\(\sin (\alpha +\pi \mathrm{/}4)=\frac{\sin \alpha +\cos \alpha }{\sqrt{2}}\)
\(\sin (\alpha −\pi \mathrm{/}4)=\frac{\sin \alpha −\cos \alpha }{\sqrt{2}}\)
Squaring both:
\({\sin }^{2}(\alpha +\pi \mathrm{/}4)=\frac{(\sin \alpha +\cos \alpha {)}^{2}}{2}\)
\({\sin }^{2}(\alpha −\pi \mathrm{/}4)=\frac{(\sin \alpha −\cos \alpha {)}^{2}}{2}\)
Thus, the ratio simplifies to:
\(\frac{{H}_{1}}{{H}_{2}}=\frac{(\sin \alpha +\cos \alpha {)}^{2}}{(\sin \alpha −\cos \alpha {)}^{2}}\)
Using the identity:
\((\sin \alpha +\cos \alpha {)}^{2}=1+\sin 2\alpha\)
\((\sin \alpha −\cos \alpha {)}^{2}=1−\sin 2\alpha\)
\(\frac{{H}_{1}}{{H}_{2}}=\frac{1+\sin 2\alpha }{1−\sin 2\alpha }\)
Step 4: Selecting the Correct OptionComparing with the given options, the correct answer is:
\(A\ \frac{1+\sin 2\alpha }{1−\sin 2\alpha }\)
The position vector of a moving body at any instant of time is given as \(\vec{r}=\left(5{t}^{2}\hat{ı}-5t\hat{ȷ}\right)m\). The magnitude and direction of velocity at t = 2 s is,
Options are free to see. Unlock the correct answer and full explanation with Pass.
A body of mass \(2\) kg moving with velocity of \({\vec{\mathrm{v}}}_{\mathrm{in}}=3\hat{\mathrm{i}}+4\hat{\mathrm{j}}{\mathrm{ms}}^{-1}\) enters into a constant force field of \(6\) N directed along positive z -axis. If the body remains in the field for a period of \(\frac{5}{3}\) seconds, then velocity of the body when it emerges from force field is
[JEE Main 2025, 8 Apr (Shift 1)]
Options are free to see. Unlock the correct answer and full explanation with Pass.
A particle moving in a circle of radius R with uniform speed takes time T to complete one revolution. If this particle is projected with the same speed at an angle \(\theta\) to the horizontal, the maximum height attained by it is equal to 4R. The angle of projection \(\theta\) is then given by:
Options are free to see. Unlock the correct answer and full explanation with Pass.
If the angles of projection for two projectiles are \(3{0}^{∘}\) and \(6{0}^{∘}\), what is the ratio of their velocities at maximum height?
Options are free to see. Unlock the correct answer and full explanation with Pass.
A particle moving in a circle of radius R with uniform speed takes time T to complete one revolution. If this particle is projected with the same speed at an angle \(\theta\) to the horizontal, the maximum height attained by it is equal to 4R. The angle of projection \(\theta\) is then given by:
Options are free to see. Unlock the correct answer and full explanation with Pass.
If the angles of projection for two projectiles are \(3{0}^{∘}\) and \(6{0}^{∘}\), what is the ratio of their velocities at maximum height?
Options are free to see. Unlock the correct answer and full explanation with Pass.
The velocity of a particle is given as \(\vec{v}=-x\hat{i}+2y\hat{j}-z\hat{k}m/s\). The magnitude of acceleration at point (1,2,4) is __________ \(m/{s}^{2}\).
[JEE Main 2026, 2 Apr (Shift 1)]
Options are free to see. Unlock the correct answer and full explanation with Pass.
If \(x\) and \(y\) coordinates of a projectile as a function of time \((t)\) are given as \(24t\) and \(43.6t-4.9{t}^{2}\), respectively, then the angle (in degrees) made by the projectile with horizontal when \(t=2\mathrm{s}\) is _________ .
[JEE Main 2026, 4 Apr (Shift 2)]
Options are free to see. Unlock the correct answer and full explanation with Pass.
The angle of projection for a projectile to have same horizontal range and maximum height is
[JEE Main 2024, 8 Apr (Shift 2)]:
Options are free to see. Unlock the correct answer and full explanation with Pass.
The position vector of a moving body at any instant of time is given as \(\vec{r}=\left(5{t}^{2}\hat{ı}-5t\hat{ȷ}\right)m\). The magnitude and direction of velocity at t = 2 s is,
[JEE Main 2025, 24 Jan (Shift 2)]
Options are free to see. Unlock the correct answer and full explanation with Pass.
A particle is projected with a velocity \(60\text{ }\text{m/s}\) at an angle \(3{0}^{∘}\) with respect to the horizontal. It reaches a height \({h}_{1}\) in the first second and height \({h}_{2}\) in the last second during its upward motion. Find the ratio of \(\frac{{h}_{1}}{{h}_{2}}\). (JEE Mains - 21 Jan 2025 - Shift I Memory Based)
Options are free to see. Unlock the correct answer and full explanation with Pass.
A particle is projected with velocity u so that its horizontal range is three times the maximum height attained by it. The horizontal range of the projectile is given as \(\frac{n{u}^{2}}{25g}\), where value of n is :
(Given ' g ' is the acceleration due to gravity).
[JEE Main 2025, 3 Apr (Shift 2)]
Options are free to see. Unlock the correct answer and full explanation with Pass.
The angle of projection for a projectile to have same horizontal range and maximum height is
[JEE Main 2024, 8 Apr (Shift 2)]:
Options are free to see. Unlock the correct answer and full explanation with Pass.
If the two projectile are projected with the same speed and the angles of projection for two projectiles are 30° and 60° then the ratio of velocities at maximum height is:
Options are free to see. Unlock the correct answer and full explanation with Pass.
Two identical bodies, projected with the same speed at two different angles cover the same horizontal range R. If the time of flight of these bodies are 5 s and 10 s , respectively, then the value of R is _______ m
(Take \(g=10m/{s}^{2}\) )
[JEE Main 2026, 8 Apr (Shift 2)]
Options are free to see. Unlock the correct answer and full explanation with Pass.
If the radius of curvature of the path of two particles of same mass are in the ratio 3:4, then in order to have constant centripetal force, their velocities will be in the ratio of:
Options are free to see. Unlock the correct answer and full explanation with Pass.
A particle is projected with a velocity \(60\text{ }\text{m/s}\) at an angle \(3{0}^{∘}\) with respect to the horizontal. It reaches a height \({h}_{1}\) in the first second and height \({h}_{2}\) in the last second during its upward motion. Find the ratio of \(\frac{{h}_{1}}{{h}_{2}}\). (JEE Mains - 21 Jan 2025 - Shift I Memory Based)
Options are free to see. Unlock the correct answer and full explanation with Pass.
A ball of mass 100 g is projected with velocity \(20\mathrm{m}/\mathrm{s}\) at \(60^\circ\) with horizontal. The decrease in kinetic energy of the ball during the motion from point of projection to highest point is
[JEE Main 2025, 22 Jan (Shift 2)]
Options are free to see. Unlock the correct answer and full explanation with Pass.
If the two projectile are projected with the same speed and the angles of projection for two projectiles are 30° and 60° then the ratio of velocities at maximum height is:
Options are free to see. Unlock the correct answer and full explanation with Pass.
Two balls with same mass and initial velocity, are projected at different angles in such a way that maximum height reached by first ball is 8 times higher than that of the second ball. \({\mathrm{T}}_{1}\) and \({\mathrm{T}}_{2}\) are the total flying times of first and second ball, respectively, then the ratio of \({\mathrm{T}}_{1}\) and \({\mathrm{T}}_{2}\) is :
[JEE Main 2025, 8 Apr (Shift 1)]
Options are free to see. Unlock the correct answer and full explanation with Pass.
A butterfly is flying with a velocity \(4\sqrt{2}m/s\) in North - East direction. Wind is slowly blowing at \(1m/s\) from North to South. The resultant displacement of the butterfly in 3 seconds is :
[JEE Main 2021, 20 Jul (Shift 1)]
Options are free to see. Unlock the correct answer and full explanation with Pass.
Two projectiles A and B are thrown with initial velocities of 40 m/s and 60 m/s at angles \(30^\circ\) and \(60^\circ\) with the horizontal respectively. The ratio of their ranges respectively is \(\left(g=10m/{s}^{2}\right)\)
[JEE Main 2023, 8 Apr (Shift 1)]
Options are free to see. Unlock the correct answer and full explanation with Pass.
Two projectiles A and B are thrown with initial velocities of 40 m/s and 60 m/s at angles 30° and 60° with the horizontal respectively. The ratio of their ranges respectively is (g = 10 m/s2)
Options are free to see. Unlock the correct answer and full explanation with Pass.
A bomb is dropped by fighter plane flying horizontally. To an observer sitting in the plane, the trajectory of the bomb is a:
[JEE Main 2021, 26 Aug (Shift 2)]
Options are free to see. Unlock the correct answer and full explanation with Pass.
The initial speed of a projectile fired from ground is \(u\). At the highest point during its motion, the speed of projectile is \(\frac{\sqrt{3}}{2} u\). The time of flight of the projectile is:
Options are free to see. Unlock the correct answer and full explanation with Pass.
Two projectiles are projected at \(30^\circ\) and \(60^\circ\) with the horizontal with the same speed. The ratio of the maximum height attained by the two projectiles respectively is:
<!--td {border: 1px solid #cccccc;}br {mso-data-placement:same-cell;}-->
Options are free to see. Unlock the correct answer and full explanation with Pass.
The maximum vertical height to which a man can throw a ball is 136 m. The maximum horizontal distance upto which he can throw the same ball is
[JEE Main 2023, 24 Jan (Shift 1)]
Options are free to see. Unlock the correct answer and full explanation with Pass.
A bomb is dropped by fighter plane flying horizontally. To an observer sitting in the plane, the trajectory of the bomb is a:
Options are free to see. Unlock the correct answer and full explanation with Pass.
The range of the projectile projected at an angle of \(15^\circ\) with horizontal is 50m. If the projectile is projected with same velocity at an angle of \(45^\circ\) with horizontal, then its range will be:
Options are free to see. Unlock the correct answer and full explanation with Pass.
A particle moves such that its position vector \(\vec{r}(t)=\cos \omega t \hat{i}+\sin \omega t \hat{j}\) where \(\omega\) is a constant and \(t\) is time. Then which of the following statements is true for the velocity \(\vec{v}(t)\) and acceleration \(\vec{a}(t)\) of the particle:
[JEE Main 2020, 8 Jan (Shift 2)]
Options are free to see. Unlock the correct answer and full explanation with Pass.
The trajectory of projectile, projected from the ground is given by \(y=x-\frac{{x}^{2}}{20}\). Where x and y are measured in meter. The maximum height attained by the projectile will be:
[JEE Main 2023, 8 Apr (Shift 2)]
Options are free to see. Unlock the correct answer and full explanation with Pass.
A stone is projected at angle \(30^\circ\) to the horizontal. The ratio of kinetic energy of the stone at point of projection to its kinetic energy at the highest point of flight will be
[JEE Main 2023, 29 Jan (Shift 1)]
Options are free to see. Unlock the correct answer and full explanation with Pass.
Two objects are projected with the same velocity 'u' however at different angles \(\alpha\) and \(\beta\) with the horizontal. If \(\alpha +\beta =90^\circ\), the ratio of horizontal range of the first object to the \({2}^{\text{nd }}\) object will be:
[JEE Main 2023, 25 Jan (Shift 2)]
Options are free to see. Unlock the correct answer and full explanation with Pass.
The maximum vertical height to which a man can throw a ball is 136 m. The maximum horizontal distance upto which he can throw the same ball is:
[JEE Main 2023, 24 Jan (Shift 1)]
Options are free to see. Unlock the correct answer and full explanation with Pass.
For a body projected at an angle with the horizontal from the ground, choose the correct statement.
[JEE Main 2023, 1 Feb (Shift 2)]
Options are free to see. Unlock the correct answer and full explanation with Pass.
A stone is projected at angle \(30^\circ\) to the horizontal. The ratio of kinetic energy of the stone at point of projection to its kinetic energy at the highest point of flight will be
Options are free to see. Unlock the correct answer and full explanation with Pass.
A mosquito is moving with a velocity \(\vec{v}=0.5{t}^{2}\hat{i}+3t\hat{j}+9\hat{k}m/s\) and accelerating in uniform conditions. What will be the direction of acceleration of mosquito after 2 s ?
[JEE Main 2021, 16 Mar (Shift 2)]
Options are free to see. Unlock the correct answer and full explanation with Pass.
A gun fires two bullets at \(60^{\circ}\) and \(30^{\circ}\) with horizontal. The bullets strike at some horizontal distance. The ratio of maximum height for the two bullets is in the ratio of
Options are free to see. Unlock the correct answer and full explanation with Pass.
Given below are two statements : one is labelled as Assertion A and the other is labelled as Reason R.
Assertion A: When a body is projected at an angle \(45^\circ\), it's range is maximum.
Reason R: For maximum range, the value of \(\sin 2\theta\) should be equal to one.
In the light of the above statements, choose the correct answer from the options given below:
[JEE Main 2023, 6 Apr (Shift 1)]
Options are free to see. Unlock the correct answer and full explanation with Pass.
The initial speed of a projectile fired from ground is u. At the highest point during its motion, the speed of projectile is \(\frac{\sqrt{3}}{2}u\). The time of flight of the projectile is:
[JEE Main 2023, 31 Jan (Shift 1)]
Options are free to see. Unlock the correct answer and full explanation with Pass.
Two guns \( A \) and \( B \) can fire bullets at speeds \( 1 \mathrm{~km} / \mathrm{s} \) and \( 2 \mathrm{~km} / \mathrm{s} \), respectively. From a point on a horizontal ground, they are fired in all possible directions. The ratio of maximum areas covered by the bullets on the ground fired by the two guns is
Options are free to see. Unlock the correct answer and full explanation with Pass.
Two objects are projected with same velocity ' \( u \) ' however at different angles \( \alpha \) and \( \beta \) with the horizontal. If \( \alpha+\beta=90^{\circ} \), the ratio of horizontal range of the first object to the \( 2 \) nd object will be :
[JEE Main 2023, 25 Jan (Shift 2)]
Options are free to see. Unlock the correct answer and full explanation with Pass.
For a body projected at an angle with the horizontal from the ground, choose the correct statement.
Options are free to see. Unlock the correct answer and full explanation with Pass.
Match List-I with List-II.
| List-I | List-II | ||
| (A) | \(\omega L>\frac{1}{\omega C}\) | (I) | Current is in phase with emf |
| (B) | \(\omega L=\frac{1}{\omega C}\) | (II) | Current lags behind the applied emf |
| (C) | \(\omega L<\frac{1}{\omega C}\) | (III) | Maximum current occurs |
| (D) | Resonant frequency | (IV) | Current leads the emf |
Choose the correct answer from the options given below:
[JEE Main 2021, 22 Jul (Shift 2)]
Options are free to see. Unlock the correct answer and full explanation with Pass.
The ranges and heights for two projectiles projected with the same initial velocity at angles \(42^{\circ}\) and \(48^{\circ}\) with the horizontal are \(\mathrm{R}_1, \mathrm{R}_2\) and \(\mathrm{H}_1, \mathrm{H}_2\) respectively. Choose the correct option:
Options are free to see. Unlock the correct answer and full explanation with Pass.
Given below are two statements : one is labelled as Assertion A and the other is labelled as Reason R.
Assertion A : When a body is projected at an angle 45°, it’s range is maximum.
Reason R : For maximum range, the value of \(\sin 2\theta\) should be equal to one.
In the light of the above statements, choose the correct answer from the options given below :
[JEE Main 2023, 6 Apr (Shift 1)]
Options are free to see. Unlock the correct answer and full explanation with Pass.
A bomb is dropped by a fighter plane flying horizontally. To an observer sitting in the plane, the trajectory of the bomb is a:
[JEE Main 2021, 26 Aug (Shift 2)]
Options are free to see. Unlock the correct answer and full explanation with Pass.
A projectile is projected at \(30^\circ\) from horizontal with initial velocity \(40m{s}^{-1}\). The velocity of the projectile at t = 2 s from the start will be:(Given \(g=10m/{s}^{2}\) )
[JEE Main 2023, 11 Apr (Shift 2)]
Options are free to see. Unlock the correct answer and full explanation with Pass.
The range of the projectile projected at an angle of \(15^\circ\) with horizontal is 50m. If the projectile is projected with same velocity at an angle of \(45^\circ\) with horizontal, then its range will be:
[JEE Main 2023, 10 Apr (Shift 1)]
Options are free to see. Unlock the correct answer and full explanation with Pass.
A butterfly is flying with a velocity \(4\sqrt{2}\mathrm{m}/\mathrm{s}\) in North East direction. Wind is slowly blowing at 1 m/s from North to South. The resultant displacement of the butterfly in 3 seconds is:
Options are free to see. Unlock the correct answer and full explanation with Pass.
A child stands on the edge of the cliff \( 10 \mathrm{~m} \) above
the ground and throws a stone horizontally with an
initial speed of \( 5 \mathrm{~ms}^{-1} \). Neglecting the air resistance,
the speed with which the stone hits the ground will
be \( \mathrm{ms}^{-1} \) (given, \( \mathrm{g}=10 \mathrm{~ms}^{-2} \) ).
[JEE Main 2023, 1 Feb (Shift 1)]
Options are free to see. Unlock the correct answer and full explanation with Pass.
Two projectiles are projected at \(30^\circ\) and \(60^\circ\) with the horizontal with the same speed. The ratio of the maximum height attained by the two projectiles respectively is:
[JEE Main 2023, 10 Apr (Shift 2)]
<!--td {border: 1px solid #cccccc;}br {mso-data-placement:same-cell;}-->
Options are free to see. Unlock the correct answer and full explanation with Pass.
Practice more JEE Physics PYQs
Browse every Physics chapter, or explore the full JEE question bank.
All Physics chapters →