Let the parabola \(y=x^2+p x-3\) cuts the coordinate axes at P , \(\mathbf{Q}\) and \(\mathbf{R}\). A circle with centre…

Let the parabola \(y=x^2+p x-3\) cuts the coordinate axes at P , \(\mathbf{Q}\) and \(\mathbf{R}\). A circle with centre \(( -1,-1 )\) passes through \(\mathbf{P}, \mathbf{Q}\) and \(R\), then the area of triangle PQR. (24 Jan, Shift I, Memory Based)