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If 2 and 6 are the roots of the equation \(a{x}^{2}+bx+1=0\), then the quadratic equation, whose roots are \(\frac{1}{2a…

Q1

If 2 and 6 are the roots of the equation \(a{x}^{2}+bx+1=0\), then the quadratic equation, whose roots are \(\frac{1}{2a+b}\) and \(\frac{1}{6a+b}\), is

[JEE Main 2024, 4 Apr (Shift 1)]

a

\({x}^{2}+8x+12=0\)

b

\(4{x}^{2}+14x+12=0\)

c

\(2{x}^{2}+11x+12=0\)

d

\({x}^{2}+10x+16=0\)

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