Let the foot of perpendicular from the point \((\lambda ,2,3)\) on the line \(\frac{x-4}{1}=\frac{y-9}{2}=\frac{z-5}{1}\) be the point \((1,\mu ,2)\). Then the distance between the lines \(\frac{x-1}{2}=\frac{y-2}{3}=\frac{z+4}{6}\) and \(\frac{x-\lambda }{2}=\frac{y-\mu }{3}=\frac{z+5}{6}\) is equal to:

[JEE Main 2026, 8 Apr (Shift 2)]

Question

Let the foot of perpendicular from the point \((\lambda ,2,3)\) on the line \(\frac{x-4}{1}=\frac{y-9}{2}=\frac{z-5}{1}\) be the point \((1,\mu ,2)\). Then the distance between the lines \(\frac{x-1}{2}=\frac{y-2}{3}=\frac{z+4}{6}\) and \(\frac{x-\lambda }{2}=\frac{y-\mu }{3}=\frac{z+5}{6}\) is equal to:

[JEE Main 2026, 8 Apr (Shift 2)]

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Let the foot of perpendicular from the point \((\lambda ,2,3)\) on the line \(\frac{x-4}{1}=\frac{y-9}{2}=\frac{z-5}{1}\…

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