🛠️ JEE➗ Maths

Let the ellipse \(3{\mathrm{x}}^{2}+{\mathrm{py}}^{2}=4\) pass through the centre \(C\)of the circle \({\mathrm{x}}^{2}+…

Q1

Let the ellipse \(3{\mathrm{x}}^{2}+{\mathrm{py}}^{2}=4\) pass through the centre \(C\)of the circle \({\mathrm{x}}^{2}+{\mathrm{y}}^{2}-2\mathrm{x}-4\mathrm{y}-11=0\) of radius \(r\). Let \({f}_{1},{f}_{2}\) be the focal distances of the point \(C\)on the ellipse. Then \(6{\mathrm{f}}_{1}{\mathrm{f}}_{2}-\mathrm{r}\) is equal to

[JEE Main 2025, 8 Apr (Shift 1)]

a

\(74\)

b

\(68\)

c

\(70\)

d

\(78\)

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