🛠️ JEE➗ Maths

Let \(\alpha ,\beta ;\alpha >\beta\), be the roots of the equation \({x}^{2}-\sqrt{2}x-\sqrt{3}=0\). Let \({P}_{n}={\alp…

Q1

Let \(\alpha ,\beta ;\alpha >\beta\), be the roots of the equation \({x}^{2}-\sqrt{2}x-\sqrt{3}=0\). Let \({P}_{n}={\alpha }^{n}-{\beta }^{n},n\in N\). Then \((11\sqrt{3}-10\sqrt{2}){P}_{10}+(11\sqrt{2}+10){P}_{11}-11{P}_{12}\) is equal to

[JEE Main 2024, 9 Apr (Shift 2)]

a

\(11\sqrt{2}{P}_{9}\)

b

\(10\sqrt{2}{P}_{9}\)

c

\(10\sqrt{3}{P}_{9}\)

d

\(11\sqrt{3}{P}_{9}\)

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