🛠️ JEE➗ Maths

In the expansion of \({\left(9x-\frac{1}{3\sqrt{x}}\right)}^{18},x>0\), if the term independent of \(x\) is \((221)k\), …

Q1

In the expansion of \({\left(9x-\frac{1}{3\sqrt{x}}\right)}^{18},x>0\), if the term independent of \(x\) is \((221)k\), then \(k\) is equal to:

[JEE Main 2026, 4 Apr (Shift 2)]

a

\(84\)

b

\(78\)

c

\(168\)

d

\(198\)

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