🛠️ JEE➗ Maths

\({x}^{2}+{y}^{2}-\alpha x-\beta y+\gamma =0\), this circle touches \(x\) axis at \((a,0)\) and it's \(Y\) intercept is …

Q1

\({x}^{2}+{y}^{2}-\alpha x-\beta y+\gamma =0\), this circle touches \(x\) axis at \((a,0)\) and it's \(Y\) intercept is \(b\). Find \(\left(2a,{b}^{2}\right)\) in terms of \(\alpha ,\beta ,\gamma\). (28 Jan, Shift I, Memory Based)

a

\((\alpha ,{\beta }^{2}-4\gamma )\)

b

\((\alpha ,{\beta }^{2})\)

c

\((\alpha ,-4r)\)

d

\((\alpha ,r)\)

🔒
Answer & explanation — PYQ Pass

Options are free to see. Unlock the correct answer and full explanation with Pass.

Unlock · ₹149

Practice more JEE Maths PYQs

See every question on Circles, or browse the full JEE question bank.

See all questions on Circles →