🛠️ JEE➗ Maths

Let the values of \(\lambda\) for which the shortest distance between the lines \(\frac{x-1}{2}=\frac{y-2}{3}=\frac{z-3}…

Q1

Let the values of \(\lambda\) for which the shortest distance between the lines \(\frac{x-1}{2}=\frac{y-2}{3}=\frac{z-3}{4}\) and \(\frac{x-\lambda }{3}=\frac{y-4}{4}=\frac{z-5}{5}\) is \(\frac{1}{\sqrt{6}}\) be \({\lambda }_{1}\) and \({\lambda }_{2}\). Then the radius of the circle passing through the points \((0,0),\left({\lambda }_{1},{\lambda }_{2}\right)\) and \(\left({\lambda }_{2},{\lambda }_{1}\right)\) is

a

\(\frac{5\sqrt{2}}{3}\)

b

\(4\)

c

\(\frac{\sqrt{2}}{3}\)

d

\(3\)

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