If the sum $\sum_{r=1}^{30} \frac{r^2\left({ }^{30} C_r\right)^2}{{ }^{30} C_{r-1}}=\alpha \cdot 2^{29}$, then $\alpha=$ (22 Jan, Shift II, Memory Based)

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If the sum \(\sum_{r=1}^{30} \frac{r^2\left({ }^{30} C_r\right)^2}{{ }^{30} C_{r-1}}=\alpha \cdot 2^{29}\), then \(\alph…

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