\(\begin{equation} \text { Perpendicular distance from the point } P(-2,0,2) \text { to the line } \frac{x+1}{2}=\frac{y…
Q1
\(\begin{equation}
\text { Perpendicular distance from the point } P(-2,0,2) \text { to the line } \frac{x+1}{2}=\frac{y-1}{-1}=\frac{z+3}{2}
\end{equation}\) (22 Jan, Shift II, Memory Based)
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