Let $\mathbf{a}=\hat{i}-\hat{k}, \mathbf{b}=x \hat{i}+\hat{j}+(1-x) \hat{k}$, and $\mathbf{c}=y \hat{i}+x \hat{j}+(1+x-y) \hat{k}$. Then, $[\mathbf{a} \mathbf{b} \mathbf{~ c}]$ depends on:

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Let \(\mathbf{a}=\hat{i}-\hat{k}, \mathbf{b}=x \hat{i}+\hat{j}+(1-x) \hat{k}\), and \(\mathbf{c}=y \hat{i}+x \hat{j}+(1+…

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