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\(\lim _{x\to 0}\csc x\left(\sqrt{2{\cos }^{2}x+3\cos x}-\sqrt{{\cos }^{2}x+\sin x+4}\right)\) is [JEE Main 2025, 24 Jan…

Q1 FREE PREVIEW

\(\lim _{x\to 0}\csc x\left(\sqrt{2{\cos }^{2}x+3\cos x}-\sqrt{{\cos }^{2}x+\sin x+4}\right)\) is

[JEE Main 2025, 24 Jan (Shift 1)]

a

0

b

\(\frac{1}{2\sqrt{5}}\)

c

\(\frac{1}{\sqrt{15}}\)

d

\(-\frac{1}{2\sqrt{5}}\)

✓ Correct answer: d)

\(-\frac{1}{2\sqrt{5}}\)

Explanation

\(\lim _{x\to 0}\csc x\left(\sqrt{2{\cos }^{2}x+3\cos x}-\sqrt{{\cos }^{2}x+\sin x+4}\right)\)

\(=\lim _{x\to 0}\frac{2{\cos }^{2}x+3\cos x-{\cos }^{2}x-\sin x-4}{\sin x\left(\sqrt{2{\cos }^{2}x+3\cos x}+\sqrt{{\cos }^{2}x+\sin x+4}\right)}\)

\(=\lim _{x\to 0}\frac{{\cos }^{2}x+3\cos x-\sin x-4}{\sin x(\sqrt{5}+\sqrt{5})}\)

on applying, L'Hospitals rule,

\(=\lim _{x\to 0}\frac{-2\cos x\sin x-3\sin x-\cos x}{\cos x\cdot 2\sqrt{5}}=-\frac{1}{2\sqrt{5}}\)

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