🛠️ JEE➗ Maths

Consider the equation \({x}^{2}+4x-n=0\), where \(\mathrm{n}\in [20,100]\) is a natural number. Then the number of all d…

Q1

Consider the equation \({x}^{2}+4x-n=0\), where \(\mathrm{n}\in [20,100]\) is a natural number. Then the number of all distinct values of n, for which the given equation has integral roots, is equal to

[JEE Main 2025, 4 Apr (Shift 1)]

a

\(7\)

b

\(8\)

c

\(6\)

d

\(5\)

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