$\frac{\sqrt{3}\csc {20}^{^\circ }−\sec {20}^{^\circ }}{\cos {20}^{^\circ }\cos {40}^{^\circ }\cos {60}^{^\circ }\cos {80}^{^\circ }}$ is equal to [JEE Main 2026, 24 Jan (Shift 1)]

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\(\frac{\sqrt{3}\csc {20}^{^\circ }−\sec {20}^{^\circ }}{\cos {20}^{^\circ }\cos {40}^{^\circ }\cos {60}^{^\circ }\cos {…

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