🛠️ JEE➗ Maths

Line \({L}_{1}\) of slope \(2\) and line \({L}_{2}\) of slope \(\frac{1}{2}\) intersect at the origin O . In the first q…

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Line \({L}_{1}\) of slope \(2\) and line \({L}_{2}\) of slope \(\frac{1}{2}\) intersect at the origin O . In the first quadrant, \({\mathrm{P}}_{1},{\mathrm{P}}_{2},\ldots .{\mathrm{P}}_{12}\) are 12 points on line \({L}_{1}\) and \({Q}_{1},{Q}_{2},\ldots ..{Q}_{9}\) are \(9\) points on line \({\mathrm{L}}_{2}\). Then the total number of triangles, that can be formed having vertices at three of the \(22\) points \(\mathrm{O},{\mathrm{P}}_{1},{\mathrm{P}}_{2},\ldots {\mathrm{P}}_{12}\), \({\mathrm{Q}}_{1},{\mathrm{Q}}_{2},\ldots .{\mathrm{Q}}_{9}\), is:

a

\(1080\)

b

\(1134\)

c

\(1026\)

d

\(1188\)

✓ Correct answer: b)

\(1134\)

Explanation

Total number of \(\Delta\) are

\(={ }^9 \mathrm{C}_1{ }^{12} \mathrm{C}_2+{ }^9 \mathrm{C}_2{ }^{12} \mathrm{C}_1+{ }^1 \mathrm{C}_1{ }^9 \mathrm{C}_1{ }^{12} \mathrm{C}_1 \)
\(=594+432+108 \)
\(=1134\)

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