The number of neutrons present in the more abundant isotope of boron is 'x'. Amorphous boron upon heating with air forms…
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The number of neutrons present in the more abundant isotope of boron is 'x'. Amorphous boron upon heating with air forms a product, in which the oxidation state of boron is 'y'. The value of \(x+y\) is
[JEE Main 2024, 5 Apr (Shift 1)]
✓ Correct answer: c)
9
Explanation
Boron isotopes:
¹⁰B and ¹¹B
More abundant = ¹¹B
Neutrons = mass number − atomic number
= 11 − 5 = 6
So, x = 6
Boron + O₂ → B₂O₃
Oxidation state of boron in B₂O₃ = +3
So, y = 3
x + y = 6 + 3 = 9
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