Let \(S\) be the set of positive integral values of \(a\) for which \(\frac{a x^2+2(a+1) x+9 a+4}{x^2-8 x+32}<0, \for…
Q1 FREE PREVIEW
Let \(S\) be the set of positive integral values of \(a\) for which \(\frac{a x^2+2(a+1) x+9 a+4}{x^2-8 x+32}<0, \forall x \in R\). Then, the number of elements in \(S\) is :
[JEE Main 2024, 31 Jan (Shift 1)]
✓ Correct answer: a)
0
Explanation
Given \(\frac{a x^2+2(a+1) x+9 a+4}{x^2-8 x+32}<0 \quad \forall x \in \mathbb{R}\)
In \(x^2-8 x+32\), we have \(D=64-128<0\)
\( \therefore x^2-8 x+32>0\) \(\forall x \in \mathbb{R} \)
\( \Rightarrow a x^2+2(a+1) x+9 a+4<0\) \(\forall x \in R \)
\( \Rightarrow a<0\) and \(D<0\)
Since Question has asked for positive integral values of \(a\)
\( \therefore|S|=0\)
but we need positive integral value of a.
So, No solution
Practice more JEE Maths PYQs
See every question on Quadratic Equations, or browse the full JEE question bank.
See all questions on Quadratic Equations →